0.05*0.2=0.05*0.15+0.015*m2',
m2'=1/6 m/s,
m2'=0.17 m/s
N I C E - D A Y!
Answer:
Explanation:
The process is isothermic, as P V = constant .
work done = 2.303 n RT log P₁ / P₂
= 2.303 x 5 / 29 x 8.3 x 303 log 2 / 1 kJ
= 300.5k J
This energy in work done by the gas will come fro heat supplied as internal energy is constant due to constant temperature.
heat supplied = 300.5k J
specific volume is volume per unit mass
v / m
pv = n RT
pv = m / M RT
v / m = RT / p M
specific volume = RT / p M
option B is correct.
Answer:
5.5 km
Explanation:
First, we convert the distance from km/h to m/s
910 * 1000/3600
= 252.78 m/s
Now, we use the formula v²/r = gtanθ to get our needed radius
making r the subject of the formula, we have
r = v²/gtanθ, where
r = radius of curvature needed
g = acceleration due to gravity
θ = angle of banking
r = 252.78² / (9.8 * tan 50)
r = 63897.73 / (9.8 * 1.19)
r = 63897.73 / 11.662
r = 5479 m or 5.5 km
Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km
