The magnitude of the force acting on the object lying on a flat surface without moving is 10 N.
The given parameters;
- magnitude of force on the object, F = 10 N
- angle between the object and the horizontal flat surface = 0⁰
Apply Newton's second law of motion to determine the magnitude of the force on the object.
Due to the position of the object, the magnitude of the force acting on it is calculated as;

Therefore, the magnitude of the force acting on the object is 10 N.
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Answer:
During acceleration, you are moving across a distance over a time, but also increasing how fast we are doing it. Therefore, it means by how many meters per second the velocity changes every second
Explanation:
 
        
             
        
        
        
Answer:
t=7.33 s
Explanation:
According to Newton's second law:

because we don't want the box to slide, the acceleration has to be zero.

we know that:

Now having the acceleration, we can use the following formula.

 
        
             
        
        
        
An air mass is a large pocket of air with a uniform temperature and humidity
        
             
        
        
        
The speed of the rock at 20 m is 34.3 m/s
Explanation:
We can solve this problem by using the law of conservation of energy: the mechanical energy of the rock, sum of its potential energy + its kinetic energy) must be conserved in absence of air resistance. So we can write:
 
where
:
 is the initial potential energy
 is the initial potential energy
 is the initial kinetic energy
 is the initial kinetic energy
 is the final potential energy
 is the final potential energy
 is the final kinetic energy
 is the final kinetic energy
The equation can also be rewritten as  follows:
 
where:
m = 100 kg is the mass of the rock
 is the acceleration of gravity
 is the acceleration of gravity
 is the initial height
 is the initial height
u = 0 is the initial speed  (the rock starts at rest)
 is the final height of the rock
 is the final height of the rock
v is the final speed when h = 20 m
And solving for v, we find:

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