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svp [43]
4 years ago
9

How do u simplify this? 4r-3+6s-8r-(4s-6)

Mathematics
1 answer:
nalin [4]4 years ago
3 0
Hey there!:

4r -3 + 6s - 8r - (4s - 6)

*distribute parentheses :

=  - ( 4s ) - ( - 6 ) 

Apply minus  - plus rules

- ( - a )  = a  ;  - ( a ) = - a

 =  - 4s + 6


4r -3+ 6 s - 8r -4s + 6 = 

Group like terms :

=4r - 8r + 6s - 4s -3+6

Add similar elements: 4r - 8r= - 4r

-4r + 6s - 4s- 3+6

6s - 4s =  2s

-4r  + 2s  - 3 + 6


Add/Subtract the numbers :

-3 + 6  = 3

Therefore:

= 2s +3 - 4r

hope this helps!




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You can show your work if u want to<br> Find 2 numbers if Their sum is −7 and their difference is 14
Pepsi [2]

The larger number is (-7+14)/2 = 3.5.

The smaller number is (-7-14)/2 = -10.5.

_____

The two equations a+b=-7, a-b=14 can be solved to get these results. It is genrally convenient to solve them by adding one to the other, or subtracting one from the other.

7 0
3 years ago
The client is to receive cyclophosphamide (Cytoxan) 50 mg/kg intravenously in divided doses over 5 days. The client weighs 176 p
marishachu [46]

Answer:

800 mg

Step-by-step explanation:

As the excerpt states that the client weights 176 pounds and is to receive cyclophosphamide (Cytoxan) 50 mg/kg, we have to convert 176 pounds to kg:

1 kg → 2.20 pounds

  x   ←  176 pounds

x= (176 pounds * 1 kg)/2.20 pounds= 80 kg

Now, we have to determine the total amount of cyclophosphamide (Cytoxan) that the client has to receive:

50 mg/kg

For 80 kg: 80 kg *50 mg/kg= 4,000  mg

As the dose is divided over 5 days:

4,000 mg / 5= 800 mg

The client will receive 800 mg of cyclophosphamide each day.

6 0
3 years ago
Determine whether the three segment lengths will produce a triangle. Type yes or no in the space provided.
tresset_1 [31]

Answer:

20 , 20 , 30 will produce a triangle

Step-by-step explanation:

* Lets study how to know if the lengths of the three segments

 can formed a triangle

- It is a fact that in any triangle the sum of the smallest two sides

 must be greater than the largest side

- Lets study some examples

# If the lengths of the three segments are 5 , 6 , 7

∵ 5 and 6 are the smallest

∴ 5 + 6 = 11

∵ 11 > 7 ⇒ the sum greater than the 3rd side

∴ 5 , 6 , 7 can formed a triangle

# If the lengths of the three segments are 5 , 7 , 12

∵ 5 and 7 are the smallest

∴ 5 + 7 = 12

∵ 12 = 12 ⇒ the sum equal the 3rd side

∴ 5 , 7 , 12 can not formed a triangle

# If the lengths of the three segments are 10 , 12 , 24

∵ 10 and 12 are the smallest

∴ 10 + 12 = 22

∵ 22 < 24 ⇒ the sum less than the 3rd side

∴ 10 , 12 , 24 can not formed a triangle

* Now lets solve the problem

∵ The length of the three segments are 20 , 20 , 30

∵ 20 and 20 are the smallest

∴ 20 + 20 = 40

∵ 40 > 30 ⇒ the sum greater than the 3rd side

∴ 20 , 20 , 30 will produce a triangle

5 0
3 years ago
Solve to find side C please
Alex73 [517]

Answer:

c= 18.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj/ hyp

cos theta = a/c

cos 57 = 10/c

Multiply each side by c

c cos 57 =10

Divide each side by cos 57

c = 10/cos 57

c=18.36078459

Rounding to the nearest tenth

c= 18.4

6 0
3 years ago
Plz help me with this Im timed will mark as brainliest
viktelen [127]
Well what i got was 79.3 by finding the average by adding it all together then divided it by how many numbers
4 0
3 years ago
Read 2 more answers
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