All categories

3 years ago

If the equation x² - kx - 36 = 0 has x = 12 as one root, what is the value of k?

Mathematics

1 answer:

sergiy2304 [10]3 years ago

5 0

To solve for k, just plug in the x provided:

12^2 - k(12) - 36 = 0

144 - k(12) = 36

-k(12) = 1/4

k = -1/48

You might be interested in

Extra points! true or false i^2= sqrt -1

Nikolay [14]

Answer:

69kc

Step-by-step explanation:

gctgd if hi ghoul h have n have n v video from guessing

8 0

2 years ago

Read 2 more answers

Find g(x)-f(x). g(x)=x^2+1 and f(x)=2x+5

UkoKoshka [18]

Answer:

$g(x) - f(x) = x^{2} - 2x - 4$

Step-by-step explanation:

g(x) - f(x) = $(x^{2} + 1) - (2x + 5)$

<em><u>Multiply the -1 in then add the two expressions together.</u></em>

$(x^{2} + 1) + (-2x - 5) = x^{2} - 2x - 4$

8 0

3 years ago

During a 12-hour period, the temperature in a city dropped from a high of 60°F to a low of -25°F. What was the range of the temp

dexar [7]

29 because I got it right just kbow

4 0

3 years ago

Could someone please help ;(

Iteru [2.4K]

Answer:

a. 25/33

b. 36

c. 1/15

d. 35/12

e. 19/12

7 0

3 years ago

Read 2 more answers

Please answer this question now

Alexeev081 [22]

Answer:

$Area = 400.4 m^2$

Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

m < V = 113°

VW = u = 29 m

Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

$\frac{u}{sin(U)} = \frac{w}{sin(W)}$

U = 33°

u = VW = 29 m

W = 180 - (33+113) = 34°

w = UV = ?

$\frac{29}{sin(33)} = \frac{w}{sin(34)}$

Cross multiply

$29*sin(34) = w*sin(33)$

Divide both sides by sin(33) to make w the subject of formula

$\frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)}$

$\frac{29*sin(34)}{sin(33)} = w$

$29.77 = w$

$UV = w = 30 m$ (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

$area = \frac{1}{2}*u*w*sin(V)$

$= \frac{1}{2}*29*30*sin(113)$

$= \frac{29*30*sin(113)}{2}$

$Area = 400.4 m^2$ (to nearest tenth).

4 0

3 years ago