(A 7 out of 8
(B y is 3
(C y is 3
Use the substitution method
w(x)=9x+8
w(5)=9(5)+8
Do the parenthesis first then add because of using PEMDAS
P= Parentheses
E= Exponents
M= Multiplication
D= Division
A= Addition
S= Subtraction
45+8
=53
Answer: w(5)=53
Answer:
The 5th term is 16
Step-by-step explanation:
Given data
a= 12
say we want to find the fifth term
n=5
d= 1
The expression for the nth term given as
an = a + (n – 1) × d
Substitute
an= 12+(5-1)1
an= 12+4
an= 16
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
