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labwork [276]
3 years ago
8

When cobalt chloride is added to pure water, the co2 ions hydrate?

Chemistry
2 answers:
NeX [460]3 years ago
7 0

The question is incomplete, the complete question is:

When cobalt chloride is added to pure water, the Co2+ ions hydrate. The hydrated form then reacts with the Cl- ions to set up the equilibrium shown here:

[Co(H2O)6]^2+ + 4Cl^- ------> [CoCl4]^2- + 6H2O

(pink) (blue)

Which statement accurately describes the change that the system will undergo if water is added?

A. The color will become more blue.

B. The equilibrium will shift to the right.

C. More water will be produced.

D. More chloride ions will be produced.

E. There will be less of the hydrated cobalt ion at the new equilibrium position.

Answer:

More chloride ions will be produced.

Explanation:

When more water is added to the system,

[Co(H2O)6]^2+ + 4Cl^- ------> [CoCl4]^2- + 6H2O, the equilibrium position will shift to the left. When the equilibrium position shifts to the left, more chloride ions are produced. and the hexaaquacobalt II complex is formed and the solution turns pink as shown hence the answer given.

mrs_skeptik [129]3 years ago
3 0
Answer : The question is incomplete and the complete question is attached in the answer;

Answer 1) When HCl was added to the system of cobalt chloride it will eventually produce more Cl ions in the solutions which will shift the equilibrium to the right and make the solution look more blue than before. To accommodate extra Cl ions in the system the equilibrium gets shifted. 

Answer 2) When in the reaction system water is added the Cobalt chloride compound forms a hydrated mixture; this means the equilibrium reaction shifts to the left and produces more hydrated ions along with more chlorine ions in the solution.

Which then turns the resultant solution tinto pink in colour.

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Kat is investigating a compound and sees that it has even stronger hydrogen bonds than water. What can kat conclude is most like
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Answer:

It is higher than that of water

Explanation:

Because we now know that through experimentation, the new compound has a higher and stronger hydrogen bonds than water, the specific heat capacity will be higher.

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Which compound is a saturated hydrocarbon?<br> A) 2-pentanone B) 2-pentene C) pentane D) pentanal
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How do I find the volume of a gas at stp if it’s volume is 80.0mL at 109kPa and -12.5 degrees Celsius
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The heat of vaporization of water at the normal boiling point, 373.2 K, is 40.66 kJ/mol. The molar heat capacity of liquid water
Tatiana [17]

Answer:

\Delta _{vap}H(300.2K)=43,658\frac{J}{mol}=43.66\frac{kJ}{mol}

Explanation:

Hello!

In this case, according to the Kirchhoff's law for the enthalpy change, it is possible to compute the heat of vaporization at 300.2 K by considering the following thermodynamic route:

\Delta _{vap}H(300.2K)=Cp_{liq}(T_b-T\°)+\Delta _{vap}H\°+Cp_{vap}(T-T_B)

Whereas the first term stands for the effect of taking the liquid from 298.15 K to 373.15 K, the second term stands for the standard enthalpy of vaporization and the last term that of the vapor from the boiling point to 300.2 K; thus we plug in to obtain:

\Delta _{vap}H(300.2K)=75.37\frac{J}{mol*K} (373.2K-298.15K)+40,660\frac{J}{mol} +36.4\frac{J}{mol*K}(300.2K-373.2K)\\\\\Delta _{vap}H(300.2K)=43,658\frac{J}{mol}=43.66\frac{kJ}{mol}

Best regards!

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