Answer:
b. Beta emission, beta emission
Explanation:
A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).
Now let us look at the N/P ratio of each atom;
For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6
For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4
For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.
For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.
The enthalpy of vaporization of H2O is higher than the enthalpy of fusion of H2O, therefore vaporizing the same mass of H2O would require more heat/energy than melting the same mass of H2O.
Answer: sorry I’m late but it is 11 electrons
Explanation:
Answer:
The answer to your question is pH = 0.686
Explanation:
Data
Acetic acid = 20 ml
Final volume = 1.7 L
pH = ?
density = 1.05 g/ml
Process
1.- Calculate the mass of acetic acid
density = mass / volume
mass = density x volume
mass = 1.05 x 20
mass = 21 g
2.- Calculate the moles of acetic acid (CH₃COOH)
Molar mass = (12 x 2) + (16 x 2) + (4 x 1)
= 24 + 32 + 4
= 60 g
60 g of acetic acid ---------------- 1 mol
21 g of acetic acid ----------------- x
x = (21 x 1) / 60
x = 0.35 moles
3.- Calculate the concentration
Molarity = 0.35 moles / 1.70 L
= 0.206
4.- Calculate the pH
pH = -log[0.206]
pH = 0.686
