Answer:
0.198 s
Explanation:
Consider the motion of the block before collision
= initial velocity of block as it is dropped = 0 m/s
= acceleration = - g
= time of travel
= final velocity of block before collision
Using the kinematics equation
= mass of the bullet = 0.026 kg
= velocity of block just before collision = 750 m/s
= mass of the block = 5 kg
= final velocity of bullet block after collision = gt
Using conservation of momentum
Power = voltage(V) * current(I)
= 120 * 0.5
Power = 60 watts
How many times did the original sample lose 50% of its radioactivity ?
-- Start with. . . . . . . . . . . . 12 grams.
-- Lose half of it once. . . . . . 6 grams left.
-- Lose half of it again . . . . . 3 grams left.
-- Lose half of it again . . . . . 1.5 grams left.
-- Lose half of it again . . . . . 0.75 gram left.
-- How many times did it lose half ? 4 times.
-- How long does it take to lose half ? 4.5 days.
(That's why it's called the 'half-life'.)
-- How long did it take to lose half, 4 times ?
(4 x 4.5 days) = 18 days .
Answer:
As the areas swept by the comet shown are all equal, the travel time of the comet in each of the presented segments is also the same
Explanation:
Kepler's second law states that an object in orbit round the Sun sweeps an equal area in an equal time interval
Here we have the area swept by the comet in a particular duration of time is constant. That is a comet sweeps equal areas in its orbit around the sun in equal time. Therefore. as the areas swept by the comet shown are all equal, the travel time of the comet in each of the presented segments is also the same.
