Answer:
b. -1.5 m/s²
Explanation:
Given the following data;
Initial velocity = 15m/s
Time = 10 seconds.
Since the car came to rest, final velocity = 0m/s
To find acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.
Mathematically, acceleration is given by the equation;


Where,
a is acceleration measured in 
v and u is initial and final speed respectively, measured in 
t is time measured in seconds.
Substituting into the equation, we have;


Acceleration = -1.5 m/s²
Answer:
d. 6.0 m
Explanation:
Given;
initial velocity of the car, u = 7.0 m/s
distance traveled by the car, d = 1.5 m
Assuming the car to be decelerating at a constant rate when the brakes were applied;
v² = u² + 2(-a)s
v² = u² - 2as
where;
v is the final velocity of the car when it stops
0 = u² - 2as
2as = u²
a = u² / 2s
a = (7)² / (2 x 1.5)
a = 16.333 m/s
When the velocity is 14 m/s
v² = u² - 2as
0 = u² - 2as
2as = u²
s = u² / 2a
s = (14)² / (2 x 16.333)
s = 6.0 m
Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.
The correct option is d
A thermal reservoir can be characterized as a thermal body that is large enough that when energy is dumped into it or taken out of it, the temperature of the reservoir does not vary considerably.
<h3>What is a thermal reservoir?</h3>
A thermal reservoir is as described, a body large enough to have a very high heat capacity. This heat capacity refers to the amount of energy needed to raise the temperature by one degree.
Therefore, we can confirm that bodies with a large enough heat capacity will be considered thermal reservoirs. This is due to the fact that when energy is dumped into it or taken out of it, the temperature of the reservoir <u>does not vary considerably</u>.
To learn more about heat capacity visit:
brainly.com/question/1453843?referrer=searchResults
Answer:
V = 49.05 [m/s]
Explanation:
We can easily find the result using kinematics equations, first, we will find the distance traveled during the 5 seconds.

where:
Yo = initial position = 0
y = final position [m]
Vo = initial velocity = 0
t = time = 5 [s]
g = gravity aceleration = 9.81 [m/s^2]
The initial speed is zero, as the body drops without imparting an initial speed. Therefore:
y = 0 + (0*5) + (0.5*9.81*5^2)
y = 122.625[m]
Now using the following equation we can find the speed it reaches during the 5 seconds.
![v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f}=\sqrt{2*9.81*122.625} \\v_{f}=49.05 [m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%20%5E%7B2%7D%3D%20v_%7Bi%7D%20%5E%7B2%7D%2B%282%2Ag%2Ay%29%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2%2A9.81%2A122.625%7D%20%5C%5Cv_%7Bf%7D%3D49.05%20%5Bm%2Fs%5D)