Question

An energy storage system based on a flywheel (a rotating disk) can store a maximum of 3.7 MJ when the flywheel is rotating at 16000 revolutions per minute.

Answer 1

The moment of inertia of the flywheel is 2.63 kg-$m^{2}$

It is given that,

The maximum energy stored on the flywheel is given as

E=3.7MJ= 3.7×$10^{6}$ J

Angular velocity of the flywheel is 16000$\frac{rev}{min}$ = 1675.51$\frac{rad}{sec}$

So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :

E = $\frac{1}{2}$$Iw^{2}$

By rearranging the equation:

I = $\frac{2E}{w_{2} }$

I = 2.63 kg-$m^{2}$

Thus the moment of inertia of the flywheel is 2.63 kg-$m^{2}$.

Learn more about moment of inertia here;

brainly.com/question/13449336

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