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malfutka [58]
2 years ago
12

An energy storage system based on a flywheel (a rotating disk) can store a maximum of 3.7 MJ when the flywheel is rotating at 16

000 revolutions per minute.
Physics
1 answer:
Likurg_2 [28]2 years ago
7 0

The moment of inertia of the flywheel is 2.63 kg-m^{2}

It is given that,

The maximum energy stored on the flywheel is given as

E=3.7MJ= 3.7×10^{6} J

Angular velocity of the flywheel is 16000\frac{rev}{min} = 1675.51\frac{rad}{sec}

So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :

E = \frac{1}{2}Iw^{2}

By rearranging the equation:

I = \frac{2E}{w_{2} }

I = 2.63 kg-m^{2}

Thus the moment of inertia of the flywheel is 2.63 kg-m^{2}.

Learn more about moment of inertia here;

brainly.com/question/13449336

#SPJ4

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Which is the work required to move a charge?
bulgar [2K]

Answer:

O electric potential

Explanation:

3 0
3 years ago
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Acartravelingat15m/sstartstodeceleratesteadily.Itcomestoacompletestopin10seconds.Whatisit'sacceleration? a. 1500 m/s b. -1.5 m/s
Amiraneli [1.4K]

Answer:

b. -1.5 m/s²

Explanation:

Given the following data;

Initial velocity = 15m/s

Time = 10 seconds.

Since the car came to rest, final velocity = 0m/s

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{initial \; speed  -  final \; speed}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is initial and final speed respectively, measured in ms^{-1}

t is time measured in seconds.

Substituting into the equation, we have;

Acceleration, a = \frac{0 - 15}{10}

Acceleration, a = \frac{-15}{10}

Acceleration = -1.5 m/s²

6 0
3 years ago
A car is traveling at 7.0 m/s when the driver applies the brakes. The car moves 1.5 m before it comes to a complete stop. If the
viva [34]

Answer:

d. 6.0 m

Explanation:

Given;

initial velocity of the car, u = 7.0 m/s

distance traveled by the car, d = 1.5 m

Assuming the car to be decelerating at a constant rate when the brakes were applied;

v² = u² + 2(-a)s

v² = u² - 2as

where;

v is the final velocity of the car when it stops

0 = u² - 2as

2as = u²

a = u² / 2s

a = (7)² / (2 x 1.5)

a = 16.333 m/s

When the velocity is 14 m/s

v² = u² - 2as

0 = u² - 2as

2as = u²

s = u² / 2a

s = (14)² / (2 x 16.333)

s = 6.0 m

Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.

The correct option is d

4 0
3 years ago
A thermal reservoir can be characterized as a thermal body that is large enough that when energy is dumped into it or taken out
hammer [34]

A thermal reservoir can be characterized as a thermal body that is large enough that when energy is dumped into it or taken out of it, the temperature of the reservoir does not vary considerably.

<h3>What is a thermal reservoir?</h3>

A thermal reservoir is as described, a body large enough to have a very high heat capacity. This heat capacity refers to the amount of energy needed to raise the temperature by one degree.

Therefore, we can confirm that bodies with a large enough heat capacity will be considered thermal reservoirs. This is due to the fact that when energy is dumped into it or taken out of it, the temperature of the reservoir <u>does not vary considerably</u>.

To learn more about heat capacity visit:

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7 0
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A ball is dropped off a very tall canyon ledge.
oksano4ka [1.4K]

Answer:

V = 49.05 [m/s]

Explanation:

We can easily find the result using kinematics equations, first, we will find the distance traveled during the 5 seconds.

y =y_{o}+(v_{o}*t)+(\frac{1}{2}*g*t^{2} )

where:

Yo = initial position = 0

y = final position [m]

Vo = initial velocity = 0

t = time = 5 [s]

g = gravity aceleration = 9.81 [m/s^2]

The initial speed is zero, as the body drops without imparting an initial speed. Therefore:

y = 0 + (0*5) + (0.5*9.81*5^2)

y = 122.625[m]

Now using the following equation we can find the speed it reaches during the 5 seconds.

v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f}=\sqrt{2*9.81*122.625} \\v_{f}=49.05 [m/s]

6 0
4 years ago
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