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Viefleur [7K]
3 years ago
15

More comparing decimals

Mathematics
1 answer:
Lisa [10]3 years ago
5 0

When comparing, think of the signs as a crocodile. A crocodile will want to eat greater (bigger) numbers than smaller numbers. So, you can think of it as that way.

2. 0.5 < 0.8 ... 0.8 is greater than 0.5

5. 0.7 = 0.70 ... This is same. 0.70 just has an extra 0 which you don't need.

8. 2.9 > 2.8 ... 2.9 is greater since 9 is bigger than 8.

11. 0.65 > 0.36 ... 65 is greater than 36. Therefore, 0.65 is greater.

14. 4.50 > 4.05 ... 4.50 has a five in the tenth place. 4.05 has five in the hundredth place.

17. 6.01 < 6.1 ... 6.1 has a one in the tenth place. 6.01 has a one in the hundredth place.

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sertanlavr [38]

Answer:

yes

Step-by-step explanation:

distributing gets you 8x+ 12= 2x-2 +6x+14

8x+12=8x+12

when both sides are simplified, they are equal to each other. This means that there IS a value of x that would make the perimeters equal

not sure what the drop down answers are so hope this helps

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tatyana61 [14]

Answer:

Leave em alone or go be noisy?

Step-by-step explanation:

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The positions of two divers from the water’s surface after a dive are shown:
Sergeeva-Olga [200]
Sal: −38 feet
Sam: −45 feet
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How will the area of the circle change if it is dilated by a scale factor of 1/2? The area will be 2 times greater than the orig
coldgirl [10]
We know that

[scale factor]=1/2
[dilated area of circle]=[original area of circle]*[scale factor]²
so
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therefore

the answer is
<span>The area will be 1/4 the original</span>
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Read 2 more answers
Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg
Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) <u>Optimal solution</u>: 40.000 units of R and 10.000 of PC = $17.000

c) <u>Slack variables</u>: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) <u>Binding Constaints</u>:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is  

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.  

3 0
2 years ago
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