Answer:
x ≤ 3
Step-by-step explanation:
The expression inside the radical ≥ 0, thus
solve
9 - 3x ≥ 0 ( subtract 9 from both sides )
- 3x ≥ - 9
Divide both sides by - 3, reversing the symol as a result of dividing by a negative quantity
x ≤ 3
Any value of x less than or equal to 3 ensures
is real
Answer:
I think it's 39 I'm wrong but that's what I think sorry
Yo don't need max height
yo use 'find vertex' equestion
since leading term is negative, this equation has a max
the vertex is the max
in the form
y=ax^2+bx+c
vertex=-b/2a
-4x^2+24x-29
a=-4
b=24
vertex=-24/(2*-4)=-24/-8=3
max height is 3 feet
dunno wat the compete square is
I can do that fo ou though
move -29 off to side and undistriute -4
-4(x^2-6x)-29
complete the square, take 1/2 of -6 an square it andadd 0
-4(x^2-6x+9-9)-29
complete square
-4((x-3)^2-9)-29
move the 9 out by distributing the -9 to the -4
36
-4(x-3)^2+36-29
-4(x-3)^2+7
answer is 3rd option
Answer:
16 : 14
24 : 21
32 : 28
Step-by-step explanation: