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3 years ago

If m 1 equals 40 find the measure of 4

1 answer:

3 0

Well, visually picture 2 lines bisecting each other. The opposite angle of ∠1 is ∠3 and the opposite angle of ∠2 is ∠4.

Remember, when all 4 angles are added together, it equals 180 :)

Also, remember that the opposite angles are always the same.

So, because ∠3 is opposite of ∠1, and ∠1 = 40°, ∠3 also equals 40°

So, simply subtract 80° from 180° because you add the two angles together.

180° - 80° = 100°

Divide 100° by 2, because there are 2 angles left :)

100° / 2 = 50°

So, ∠2 and ∠4 = 50°

SO YOUR ANSWER IS :

∠1 = 40°, ∠2 = 50°, ∠3 = 40°, ∠4 = 50°

~Hope I helped!~

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Find the area of the shaded region.

skelet666 [1.2K]

Answer:

5x12

Step-by-step explanation:

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3 years ago

The wind speed near the center of a tornado is represented by the equation S=93logd+65, where d is the distance, in miles, that

dezoksy [38]

Answer:

Therefore,

Wind speed of a Tornado when it travels 4 miles is 121.0 miles per hour.

Step-by-step explanation:

Given:

The wind speed near the center of a tornado is represented by the equation,

$S=93\log d+65$

Where,

d = the distance, in miles

S = the wind speed, in miles per hour.

To Find:

S = ? at d = 4 miles

Solution:

We have

$S=93\log d+65$ .........Given

Substitute d = 4 in above equation we get,

$S=93\log 4 + 65=93\times 0.602 +65=120.99$

Rounding the answer to the nearest tenth we have

$S=121.0\ mph$

Therefore,

Wind speed of a Tornado when it travels 4 miles is 121.0 miles per hour.

4 0

3 years ago

Find the extreme values of f(x y)=xy subject to the constraint x^2 + y^2 -4 = 0

KATRIN_1 [288]

Via Lagrange multipliers:

$L(x,y,\lambda)=xy+\lambda(x^2+y^2-4)$

$L_x=y+2\lambda x=0$
$L_y=x+2\lambda y=0$
$L_\lambda=x^2+y^2-4=0$

$yL_x=y^2+2\lambda xy=0$
$xL_y=x^2+2\lambda xy=0$
$\implies yL_x-xL_y=y^2-x^2=0\implies y^2=x^2$
$\implies x^2+y^2=4=2x^2\implies x^2=2\implies x=\pm\sqrt2\implies y=\pm\sqrt2$

So we have four critical points to consider, $(\sqrt2,\sqrt2),(-\sqrt2,\sqrt2),(\sqrt2,-\sqrt2),(-\sqrt2,-\sqrt2)$ . If both coordinates are positive or both are negative, we get a maximum value of $(\pm\sqrt2)^2=2$ ; otherwise, we get a minimum of $(-\sqrt2)(\sqrt2)=-2$ .

4 0

3 years ago

Now that his car is 5 years old, he would like to know whether the variability of gas mileage has changed. He recorded the gas m

Kamila [148]

Answer:

Now that his car is 5 years old, he would like to know whether the variability of gas mileage has changed. He recorded the gas mileage from his last eight fill-ups; these are listed here. Conduct a test at a 10% significance level to infer whether the variability has changed.

Step-by-step explanation:

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3 years ago

What is the solution to the equation below round your answer to two decimal decimal places log4 x=2.1

nekit [7.7K]

Answer:

Step-by-step explanation:

log4x = 2.1

logx/log4 = 2.1

logx = log(4) x 2.1

logx = 1.264

x = 10^(1.264)

x = 18.38 (to two d.p)

8 0

3 years ago