Ask question

Ask question

All categories

4 years ago

6

You short-circuit a 9 volt battery by connecting a short wire from one end of the battery to the other end. If the current in th

e short circuit is measured to be 16 amperes, what is the internal resistance of the battery?

1 answer:

horsena [70]4 years ago

3 0

Answer:

The internal resistance of the battery is 0.562 ohms.

Explanation:

Given that,

Voltage of battery, V = 9 volts

Current in the short circuit, I = 16 A

In case of short circuit, the external resistance of the circuit will be equal to 0.

So, we can say that, the internal resistance of the battery is given by :

$r=\dfrac{V}{I}\\\\r=\dfrac{9}{16}\\\\r=0.562\ \Omega$

So, the internal resistance of the battery is 0.562 ohms.

You might be interested in

Which are benefits of using nuclear power plants to generate electricity? Check all that apply.

lesya [120]

Below are the benefits <span>of using nuclear power plants to generate electricity:

</span><span>Nuclear power plants use simple power plant designs not vulnerable to human error or natural disasters.
</span>
<span>Nuclear power plants use renewable fuel.
</span>
<span>Nuclear power plants produce a large amount of energy for a small mass of fuel. Nuclear power plants produce no toxic waste products.
</span><span>
- The outflows of nursery gasses and in this manner the commitment of atomic power plants to an Earth-wide temperature boost is accordingly moderately little. The era of power through atomic vitality lessens the measure of vitality produced from non-renewable energy sources (coal and oil). Less utilization of petroleum products implies bringing down ozone-depleting substance outflows (CO2 and others).

</span>

3 0

3 years ago

Read 2 more answers

The mass of earth 6*10^24kg and radius is 400kg Now find the value of acceleration due to gravity when a object is 3600km from t

Katen [24]

Answer:

Explanation:

the Earth is 6 xx 10^(24) kg and its radius is 6400 km. Find the acceleration due to gravity on the surface of the Earth. Updated On: 7-4-2021

6 0

3 years ago

Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba

Allushta [10]

The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
$p_i = p_1-p_2 = mv-mv =0$
So, the final momentum must be zero as well:
$p_f = 0$
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
$p_f = mv_1 + mv_2 = 0$
From which
$v_1 = -v_2$

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is $\frac{1}{2} mv^2$ . Therefore, the total kinetic energy before the collision is
$K_i = \frac{1}{2} mv^2 + \frac{1}{2} mv^2 = mv^2$
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
$K_f = K_i = mv^2$ (1)
But the final kinetic energy, Kf, is also
$K_f = \frac{1}{2} mv_1^2 + \frac{1}{2}mv_2^2$
Substituting $v_1 = -v_2$ as we found in the conservation of momentum, this becomes
$K_f = mv_2 ^2$
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write
$mv_2^2 = mv^2$

Therefore, the two final speeds of the balls are
$v_2 = v$
$v_1 = -v_2 = -v$

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

8 0

3 years ago

The most energy-efficient way to send a spacecraft to the Moon is to boost its speed while it is in circular orbit about the Ear

jeyben [28]

Answer:

98.33 %

Explanation:

On an elliptical orbit, angular momentum will be conserved .

Angular momentum = I ω = mvR

So mv₁R₁ = mv₂R₂

= v₁R₁ = v₂R₂

where v₁ is velocity and R₁ radius in low orbit (perigee)and v₂ and R₂ is velocity and radius in high orbit ( apogee ).

Here R₁ = Radius of the earth , R₂ is distance between moon and earth.

R₁ / R₂ = 1/60

v₁ /v₂ = R₂ / R₁ = 60

v₂ / v₁ = 1 / 60

1 - (v₂ / v₁ ) = 1 -( 1 / 60)

(v₁ -v₂)/v₁ = ( 60-1 )/60

(v₁ -v₂)/v₁ x 100 = 5900/60 = 98.33 %

5 0

4 years ago

A convex mirror of focal length 34 cm forms an image of a soda bottle at a distance of 18 cm behind the mirror. The height of th

Mademuasel [1]

<h2>Answers:</h2>

In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

<h2 /><h2>a) Position of the soda bottle (the object) </h2><h2 />

The Mirror equation is:

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$ (1)

Where:

$f$ is the focal distance

$u$ is the distance between the object and the mirror

$v$ is the distance between the image and the mirror

We already know the values of $f$ and $v$ , let's find $u$ from (1):

$u=\frac{v.f}{v-f}$ (2)

Taking into account the explanation at the beginign of this asnswer:

$f=-34cm$ and $v=-18cm$

The <u>negative signs</u> indicate the <u>focal distance</u> and the <u>distance between the image and the mirror are virtual </u>

Then:

$u=\frac{(-18cm)(-34cm)}{-18cm-(-34cm)}$

$u=38.25cm$ (3) >>>>Position of the soda bottle

<h2>b) magnification of the image </h2><h2 />

The magnification $m$ of the image is given by:

$m=-\frac{v}{u}$ (4)

$m=-\frac{(-18cm)}{38.25cm}$

$m=0.47$ (5)>>>the image is 0.47 smaller than the object

<h2>The fact that this value is positive means the image is upright </h2>

<h2>c) Describe the image </h2><h2 />

According to the explanations and results obtained in the prior answers, the correct option is 9:

<h2>The image is <u>virtual, upright, smaller</u> than the object </h2><h2 /><h2>d) Height of the soda bottle (object) </h2>

Another way to find the magnification is by the following formula:

$m=\frac{h_{i}}{h_{o}}$ (6)

Where:

$h_{i}$ is the image height

$h_{o}$ is the object height

We already know the values of $m$ and $h_{i}$ , let's find $h_{o}$ :

$h_{o}=\frac{h_{i}}{m}$ (7)

$h_{o}=\frac{6.8cm}{0.47}$

$h_{o}=14.46cm$ (8) >>>height of thesoda bottle

6 0

3 years ago