Answer:
f = 5.65 Hz
Explanation:
The fundamental frequency of a string is given by following formula:
f = v/2L
where,
f = fundamental frequency
v = speed of wave = √(TL/m)
L = Length of String
m = Mass of String
T = Tension in String
Therefore,
f = √(TL/m)/2L
2f = √(T/Lm)
For initial condition:
T₁ = 600 N
f₁ = 110 Hz
2(110 Hz) = √(600 N/Lm)
√(600 N)/220 Hz = √Lm
Lm = 0.01239 N/s²
Now, for changed tension:
2f₂ = √(540 N/0.01239 N/s²)
f₂ = 208.7 Hz/2
f₂ = 104.35 Hz
So, the beat frequency will be:
f = f₁ - f₂
f = 110 Hz - 104.35 Hz
<u>f = 5.65 Hz</u>
Answer:
(a) Radius = 4.6 x 10^11 m
(b) speed = 16.96 km/s
Explanation:
Time period, T = 5.4 earth years
mass of sun, M = 1.989 x 10^30 kg
(a) Let the orbital radius is R.
use the formula of period
(b) Let the speed is v.
The answer is Density. The Density of the <span>glass is measured with bromoform and bromobenzene mixtures in a column. </span>Density measurement<span> is done using Density gradient </span>columns. It is a <span> temperature-controlled density </span>column<span> containing a </span>mixture<span> of b</span>romobenzene<span> and </span>bromoform.
Answer:
The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2
Explanation:
Given:
F = 550 N
m = 1000 kg
To Find:
a = ?
Solution:
So by the equation by Newton's 2nd Law of Motion,
F = m x a
550 N = 1000 kg x a
a = 550 N/ 1000 kg
a = 0.55 m/s^2
Therefore,
The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2
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