Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
D none of the above
all of them is related to energy and motion , not to positioning.
Answer:
I attached a PFD with the answer to your question and roughly 50 others involving acceleration and how to calculate it. This PDF gives you the answers to all the question whilst showing you an in-depth explanation on how they got the answer. Hopefully that helps
Explanation:
May I have brainliest please? :)
