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3 years ago

Find the volume of an object with a density of 3.2 g/mL and a mass of 12 g.

Physics

2 answers:

dusya [7]3 years ago

8 0

Answer:

the mass is 45 g

Explanation:

ddd [48]3 years ago

3 0

The mass is 45g happy to help!

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The speed of the center of the earth as it orbits the sun is 107257 kmph and the absolute angular velocity of the earth about it

Sindrei [870]

Answer with Explanation:

We are given that

Speed , $v_0$ =107257 kmph

Angular velocity, $\omega=7.292\times 10^{-5} rad/s$

Radius of earth,r= $6371 km=6371000 m$

1 km=1000 m

Linear velocity, $v=r\omega=6371000\times 7.292\times 10^{-5}=464.57 m/s$

Linear velocity, $v=464.57\times \frac{18}{5}=1672.46 km/h$

Velocity at point A, $v_A=-vi+v_0 j=-1672.46 i+107257j kmph$

Velocity at point B, $v_B=v_0j-vj=107257j-1672.46j=105584.54j kmph$

Velocity at point C, $v_C=v_0j+vi=1672.46 i+107257j kmph$

Velocity at point D, $v_D=v_0j+vj=107257j+1672.46j=108929.46jkmph$

3 0

3 years ago

1. Which of the following is correct about the sampling distribution of the sample mean

joja [24]

Answer:

In my opinion I think that the answer is C sorry If I get this wrong.

5 0

3 years ago

Pluto’s diameter is approximately 2370 km, and the diameter of its satellite Charon is 1250 km. Although the distance varies, th

MissTica

Answer:

$r_{cm} = 2520.5 km$

Explanation:

As we know that mass is the product of volume and density

so we will have

$M = \rho V$

here we have

$M = \rho(\frac{4}{3}\pi r^3)$

so we will have

$\frac{M_p}{M_c} = (\frac{r_p}{r_c})^3$

so we will have

$\frac{M_p}{M_c} = (\frac{2370}{1250})^3$

$M_p = 6.81 M_c$

now let the position of Pluto is at origin so we have

$r_{cm} = \frac{M_p (0) + M_c(19700)}{M_p + M_c}$

$r_{cm} = \frac{19700}{\frac{M_p}{M_c} + 1}$

$r_{cm} = \frac{19700}{6.81 + 1}$

$r_{cm} = 2520.5 km$

5 0

4 years ago

A golf ball is launched horizontally at a speed of 11 meters per second and a high of 6.4 m above the ground. How long will it t

Serjik [45]

The answer is A.

t = ( 2h / g )^1/2 = ( 2 x 6.4 / 9.8 )^1/2 = 1.14s

8 0

2 years ago

the current flowing in an appliance connected to a 120V source is 2A. How many kilowatt-hours of electrical energy does the appl

skad [1K]

Answer:

0.96 kWh

Explanation:

First of all, we can find the power of the appliance using the formula:

$P=VI$

where

V = 120 V is the voltage of the source

I = 2 A is the current

Substituting,

$P(120 V)(2 A)=240 W = 0.24 kW$

Now we want to find the amount of energy used by the applied in a time of

t = 4 h

The amount of energy is given by

$E=Pt$

where

P = 0.24 kW

t = 4 g

Substituting,

$E=(0.24 kW)(4 h)=0.96 kWh$

8 0

4 years ago