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3 years ago

13

A quiz consists of 6 questions. The instructor would like to create different versions of the quiz where the order of the proble

ms are scrambled for each student. In how many ways can this be done?

1 answer:

Alisiya [41]3 years ago

4 0

I believe you would do 6! which is 6*5*4*3*2*1 to find the number of solutions.

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Convert 3.7 kilogram into gram

tigry1 [53]

<em><u>Answer:</u></em>

3700 grams

<em><u>Step-by-step explanation:</u></em>

A kilogram is 1000 grams so if we want to convert 3.7 kiograms into grams, we just have to multiply 3.7 by 1000 which gets you: 3700 grams

4 0

3 years ago

which ordered pair is a solution to the system of inequalities? {y>−2x+y≤4 (−2, −3) (0, −4) (1, 3) (1, 5)

Nadya [2.5K]

Answer:

(0, -4)

Step-by-step explanation:

Given the inequality expression

y>−2x+y≤4

This can be splitted into

y>−2x+y .... 1

and -2x+y≤4 .... 2

From1;

y>−2x+y

y - y >−2x

0 >−2x

-2x < 0

x > 0/-2

x>0

Substitute x = 0 into 2

-2(0)+ y ≤4

y≤4

Hence the solution is (0, -4)

8 0

3 years ago

Read 2 more answers

What is the surface area of the cube with the given edge length, s? Drag and drop the surface area into the box to match the edg

TEA [102]

Cube surface area = side^2 * 6
cube surface area = 2.3^2 * 6
cube surface area = 31.74 cm^2

4 0

4 years ago

Read 2 more answers

catering service offers 8 appetizers, 11 main courses, and 7 desserts. A banquet committee is to select 7 appetizers, 8 main

guapka [62]

Answer: The required number of ways is 46200.

Step-by-step explanation: Given that a catering service offers 8 appetizers, 11 main courses, and 7 desserts.

A banquet committee is to select 7 appetizers, 8 main courses, and 4 desserts.

We are to find the number of ways in which this can be done.

We know that

From n different things, we can choose r things at a time in $^nC_r$ ways.

So,

the number of ways in which 7 appetizers can be chosen from 8 appetizers is

$n_1=^8C_7=\dfrac{8!}{7!(8-7)!}=\dfrac{8\times7!}{7!\times1}=8,$

the number of ways in which 8 main courses can be chosen from 11 main courses is

$n_2=^{11}C_8=\dfrac{11!}{8!(11-8)!}=\dfrac{11\times10\times9\times8!}{8!\times3\times2\times1}=165$

and the number of ways in which 4 desserts can be chosen from 7 desserts is

$n_3=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.$

Therefore, the number of ways in which the banquet committee is to select 7 appetizers, 8 main courses, and 4 desserts is given by

$n=n_1\times n_2\times n_3=8\times165\times35=46200.$

Thus, the required number of ways is 46200.

7 0

4 years ago

How to determine if set of vectors is linearly independent?

zimovet [89]

The vectors $\{v_1,v_2,...,v_p\}\in \mathbb{R}^n$ are linearly independent if the ONLY solution to the following equation:

$c_1v_1+c_2v_2+...c_pv_p=0$

is $c_1=c_2=...=c_p=0$

7 0

3 years ago