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vaieri [72.5K]
3 years ago
13

A quiz consists of 6 questions. The instructor would like to create different versions of the quiz where the order of the proble

ms are scrambled for each student. In how many ways can this be done?
Mathematics
1 answer:
Alisiya [41]3 years ago
4 0
I believe you would do 6! which is 6*5*4*3*2*1 to find the number of solutions.
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12 decreased by 8 times a number is 36
LekaFEV [45]
8x-12=36

Let's solve your equation step-by-step.

<span><span><span>8x</span>−12</span>=36

</span>Step 1: Add 12 to both sides.

<span><span><span><span>8x</span>−12</span>+12</span>=<span>36+12

</span></span><span><span>8x</span>=48

</span>Step 2: Divide both sides by 8.

<span><span><span>8x/</span>8</span>=<span>48/8

</span></span><span>x=6

</span>Answer: x=6
5 0
3 years ago
4
Irina-Kira [14]

Answer:

t

Step-by-step explanation:

323rd century fox news has been in the past year and it is a different

6 0
3 years ago
if y varies directly as x and y is 48 when x is 48 when x is 6 which expression can be used to find the values of y when x is 2
Oksanka [162]

Answer:

the expression is

y=8x

Step-by-step explanation:

y varies directly as x is written as

y  \alpha x

introducing constant

y=kx

from the question, when y=48, x=6

substitute it in the formula

48=6k

<em>maki</em><em>ng</em><em> </em><em>k</em><em> </em><em>the</em><em> subject</em><em> </em><em>by</em><em> </em><em>divi</em><em>ding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>6</em>

<em>\frac{48}{6}  =  \frac{6k}{6}</em>

<em>k</em><em>=</em><em>8</em>

<em>put</em><em>ting</em><em> </em><em>the </em><em>va</em><em>lue</em><em> </em><em>of</em><em> </em><em>k</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>exp</em><em>ression</em><em>,</em>

<em>y</em><em>=</em><em>8</em><em>x</em>

<em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>whe</em><em>n</em><em> </em><em>x</em><em>=</em><em>2</em>

<em>y</em><em>=</em><em>8</em><em>×</em><em>2</em>

<em>y</em><em>=</em><em>1</em><em>6</em>

<em>thu</em><em>s</em><em> </em><em>the </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>whe</em><em>n</em><em> </em><em>x</em><em>=</em><em>2</em><em> </em><em>is</em><em> </em><em>1</em><em>6</em><em>.</em>

6 0
3 years ago
Read 2 more answers
A forest ranger stands at the top of a 120 foot fire tower. He spots a fire 900 feet away from the base of the tower. What is th
allochka39001 [22]

Answer: 7.6\°

Step-by-step explanation:

You need to draw a right triangle as the one attached, where \alpha is the angle of elevation from the fire to the top of the fire tower.

You need to use the Inverse trigonometric function Arctangent:

\alpha= arctan(\frac{opposite}{adjacent})

Observe the triangle. You can identify that:

opposite=120\\adjacent=900

Then, you can substitute values:

\alpha= arctan(\frac{120}{900})

Finally, evaluating, you get that the angle of elevation  from the fire to the top of the fire tower is the following:

\alpha =7.59\°

Rounded to the  the nearest tenth of a degree:

\alpha\approx7.6\°

4 0
3 years ago
Fixed Object Involved in Collision Number of Collisions Pole/post 1,416 Culvert/curb/ditch 2,516 Shrubbery/tree 2,585 Guardrail
Genrish500 [490]

Answer:

0.1358 = 13.58% probability of a fatal collision with a pole or post

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

1416 collisions with pole or post.

1416 + 2516 + 2585 + 896 + 947 + 231 + 1835 = 10426 total collisions.

a. What is the probability of a fatal collision with a pole or post?

p = \frac{1416}{10426} = 0.1358

0.1358 = 13.58% probability of a fatal collision with a pole or post

3 0
3 years ago
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