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3 years ago

13

A quiz consists of 6 questions. The instructor would like to create different versions of the quiz where the order of the proble

ms are scrambled for each student. In how many ways can this be done?

1 answer:

Alisiya [41]3 years ago

4 0

I believe you would do 6! which is 6*5*4*3*2*1 to find the number of solutions.

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Suppose a sociologist studying the sleep habits of teenagers in the U.S. randomly surveyed 1873 teenagers. Of those, 297 teenage

dem82 [27]

$\hat{p}=p\pm\frac{\sqrt{p(1-p)}}{\sqrt{n}}\\p=\frac{297}{1873}=0.1586\\ \hat{p}=0.1586\pm\frac{\sqrt{0.1586(1-0.1586)}}{\sqrt{1873}}\\=0.1586\pm\frac{\sqrt{0.1586(0.8414)}}{43.2782}}\\=0.1586\pm\frac{\sqrt{0.1334}}{43.2782}}\\=0.1586\pm\frac{0.3653}{43.2782}}\\=0.1586\pm0.0084$

5 0

3 years ago

If there are 10 people in a race how many ways can 1st 2nd 3rd places be awarded

kiruha [24]

3 slots
1st slot has 10 possible people
2nd slot has 9 possible people (1 less than previous)
3rd slot has 8 possible people

so there are 10*9*8 ways or 720 ways

4 0

3 years ago

Imagine slicing the pyramid with a plane parallel to its base and passing through the topmost point of the pyramid. What will th

Nitella [24]

Answer:

Cross sections perpendicular to the base and through the vertex will be triangles. Below, you can see a plane cutting through the pyramid, part of the pyramid removed, and the cross section. You could also take a slice parallel to the base. Cross sections parallel to the base will be hexagons.

Step-by-step explanation:

6 0

3 years ago

If two lines do not intersect , then their intersection is not exactly one point.

Dvinal [7]

If they don't intersect then there is no solution and the lines are parrell.

8 0

3 years ago

PLS HELP ASAP:Find all the missing elements:

adelina 88 [10]

Answer:

b ≈ 9.5, c ≈ 14.7

Step-by-step explanation:

Using the Sine rule in Δ ABC, that is

$\frac{a}{sinA}$ = $\frac{b}{sinB}$ , substitute values

$\frac{7}{sin23}$ = $\frac{b}{sin32}$ ( cross- multiply )

b × sin23° = 7 × sin32° ( divide both sides by sin23° )

b = $\frac{7sin32}{sin23}$ ≈ 9.5 ( to the nearest tenth )

Also

$\frac{a}{sinA}$ = $\frac{c}{sinC}$

$\frac{7}{sin23}$ = $\frac{c}{sin125}$ ( cross- multiply )

c × sin23° = 7 × sin125° ( divide both sides by sin23° )

c = $\frac{7sin125}{sin23}$ ≈ 14.7 ( to the nearest tenth )

3 0

3 years ago