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Alex787 [66]
2 years ago
14

A reflection of the pink triangle is shown. Which transformation makes this reflection?

Mathematics
1 answer:
lapo4ka [179]2 years ago
5 0

Answer:

The answer is A on the last question.......

Step-by-step explanation:


You might be interested in
Factors of 9 simple question ​
dolphi86 [110]

the factors are 1, 3, 9 i hope it helps :)

Step-by-step explanation:

bc i saidsoooo:)

6 0
2 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
2 years ago
I need help on this question as well.
Y_Kistochka [10]

8 is the answer, because 4 x 8 = 32

7 0
3 years ago
Read 2 more answers
If the side length of a square pyramid is triple and the slant height is divided by 5 what would be the formula to find the modi
valentina_108 [34]
If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)

Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)

_____
Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')
5 0
3 years ago
Subtract 7x^2−5xy+8y2 from −2x^2−15xy+9y^2
Digiron [165]

Answer

Subtract 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2

then;

-2x^2 -15xy+9y^2 - (7x^2 -5xy+8y^2)

Remove the bracket we have;

-2x^2 -15xy+9y^2 - 7x^2 + 5xy - 8y^2

Like terms are those terms which have same variable to the same power.

Combine like terms;

-9x^2 -10xy+y^2

Therefore, Subtracting 7x^2 -5xy+8y^2 from -2x^2 -15xy+9y^2 we get -9x^2 -10xy+y^2

7 0
2 years ago
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