
<u>Domain</u> <u>Range</u>
-3 ¹/₂
-2 ¹/₃
-1 0
0 -1
1 undefined
2 3
3 1¹/₂
Answer:
ABC shaded area = 36
- 72 cm²
ABC shaded area perimeter =
cm
ABCD area =
cm²
ABCD perimeter =
cm
Step-by-step explanation:
<u>Shape ABC</u>
Assuming you want the area and perimeter of the shaded part of the shape only...
<u>Area</u>
Area of a sector =
(where r is the radius and
<em> </em>
⇒ area of a sector = 
Area of triangle = 1/2 x base x height
⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²
Therefore, area of shaded area = area of sector - area of triangle
⇒ area = 36
- 72 cm²
<u>Perimeter</u>
Arc length =
(where r is the radius and
<em> </em>
⇒ arc length = 
Hypotenuse of triangle =
(where a and b are the legs of the right triangle)
⇒ hypotenuse =
cm
Therefore, perimeter = arc length + hypotenuse
⇒ perimeter =
cm
<u>Shape ABCD</u>
<u>Area</u>
Area of a semicircle =
(where r is the radius)
⇒ area of large semicircle ABC = 
⇒ area of small semicircle AD = 
⇒ area of shape ABCD = 
<u>Perimeter</u>
1/2 circumference = 
⇒ perimeter = 
Answer:
y = -
x + 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 5x + 2 ← is in slope- intercept form
with slope m = 5
Given a line with slope m then the slope of the line perpendicular to it is
= -
= - 
The line crosses the y- axis at (0, 5 ) ⇒ c = 5
y = -
x + 5 ← equation of perpendicular line
Answer:
(E) 72 w^2 is the answer
Step-by-step explanation:
outer square area is 81 w^2
inner square area is 9 w^2
subtracting outer - inner we can get the shaded area
so 81 -9= 72w^2
That would be 100(1+3).
Hope that helped :)