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3 years ago

Tony rounded each of the numbers 1183 and 1145 to the nearest hundred. Which choice correctly compares the rounded numbers

Mathematics

2 answers:

Alisiya [41]3 years ago

5 0

Answer:

1200 and 1100

Step-by-step explanation:

Tony rounded each of the numbers 1183 and 1145 to the nearest hundred.

To round the number to nearest hundred , check the digit in tens place.

If the number in tens place is greater than or equal to 5 then we add 1 in hundreds place

If the number in tens place is less than 5 then we replace the remaining digits by 0

In 1183, we have 8 in tens place so 1183 is rounded to 1200

In 1145, we have 4 in tens place so 1145 is rounded to 1100

Mamont248 [21]3 years ago

4 0

1183 rounded to the nearest hundred = 1200
1145 rounded to the nearest hundred = 1100

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An angle's complement is 35°. Find the measure of its supplement. A) 55° B) 65° C) 125° D) 155° E) 180°

kenny6666 [7]

Answer:

C) 125°

Step-by-step explanation:

Supplementary angles add to 180 degrees. Complementary angles add to 90

An angle's complement is 35°.

35+x =90

Subtract 35 from each side

35 -35+x = 90-35

x = 55

We want to find the supplement of this angle

55+y = 180

Subtract 55 from each side

55-55+y = 180-55

y= 125

The angle is 55 so its supplement is 125

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3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

Find the area of the figure ABC

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

Find the area of the semicircle

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

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3 years ago

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Answer:

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Step-by-step explanation:

Evaluate

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Open parenthesis

(-4.2 * -2.8) + (-4.2 * 4.5)

= (11.76) + (- 18.9)

= 11.76 - 18.9

= -7.14

NOTE:

Negative (-) × negative (-) = positive (+)

Positive (+) × positive (+) = positive (+)

Negative (-) × positive (+) = negative (-)

Positive (+) × negative (-) = negative (-)

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3 years ago

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garik1379 [7]

Answer:

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Step-by-step explanation:

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Hope this helps!

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2 years ago

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Gala2k [10]

Answer:

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