THE ANSWER IS C BC ITS 100% + 30%
Start with #47. To find the critical values, you must differentiate this function. x times (4-x)^3 is a product, so use the product rule. The derivative comes out to f '(x) = x*3*(4-x)^2*(-1) + (4-x)^3*1 = (4-x)^2 [-3x + 4-x]
Factoring this, f '(x) = (4-x)^2 [-3x+4-x]
Set this derivative equal to zero (0) and solve for the "critical values," which are the roots of f '(x) = (4-x)^2 [-3x+4-x]. (4-x)^2=0 produces the "cv" x=4.
[-3x+ (4-x)] = 0 produces the "cv" x=1. Thus, the "cv" are {4,1}.
Evaluate the given function at x: {4,1}. For example, if x=1, f(1)=(1)(4-1)^3, or 2^3, or 8. Thus, one of the extreme values is (1,8).
2/5 is the answer if you want a explanation pls ask me
Answer:
Solution given:
- (sinx+cosx)^2-(sinx-cosx)^2
- sin²x+2sinxcosx+cos²x-(sin²x-2sinxcosx+cos²)
- 1+2sinxcosx-1+2sinxcosx
- 2(2sinxcosx)
- 2sin2x
Step-by-step explanation:
[note: sin²x+cos²x=1]
The formula is L*H (LENGTH * HEIGHT) 9*4=36 THE AREA IS 36CM^2