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Elanso [62]
3 years ago
15

(a^2^n - a^n - 6) / (a^n + 8)  That's a power of 2n the 2n is an exponent 

Mathematics
1 answer:
Reil [10]3 years ago
7 0
Using long division, we have


a^{2}-1
____________________


a^{n}+8 | a^{2n}  -a^{n}-6

 
                -(a^{2n}+8a^{2})

                   -a^{n}-8a^{2}-6

                 -(-a^{n}+8)
                  
                       -8a^{2}-14

The parenthesis are the result of what we multiply (a^n+8) by (we multiply it by the top expression - we start with a^2 then -1), and what's not is the result of adding the parenthesis to the expression about that.

Our final result is (a^n+8)*(a^2-1)-8a^2-14
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