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Digiron [165]
3 years ago
12

Which of the following is important to consider before believing health or fitness information you find online?

Computers and Technology
1 answer:
Alinara [238K]3 years ago
5 0
<span>Which of the following is important to consider before believing health or fitness information you find online? 

The right answer is C) </span>The qualifications of the author.

We should not believe in information about health and fitness if the author isn't qualified to give it. 
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Describe a situation in which a robot may have to avoid an obstacle without coming to a complete stop before turning.
Airida [17]

A robot may have to avoid an obstacle without coming to a complete stop before turning. If the robot is able to make a wide enough, long turn. instead of stopping, then turning sharply. For example if the robot were to come across an object and can sense said object before hand. it can then take action into turning before it is close enough.

3 0
3 years ago
Read 2 more answers
Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv
elena-s [515]

Answer:

PART ONE

  1. import java.util.Scanner;
  2. public class CountToLimit {
  3.    public static void main(String[] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        int countLimit = 0;
  6.        int printVal = 0;
  7.        // Get user input
  8.        System.out.println("Enter Count Limit");
  9.        countLimit = scnr.nextInt();
  10.        do {
  11.            System.out.print(printVal + " ");
  12.            printVal = printVal + 1;
  13.        } while ( printVal<=countLimit );
  14.        System.out.println("");
  15.        return;
  16.    }
  17. }

PART TWO

  1. import java.util.Scanner;
  2. public class NumberPrompt {
  3.    public static void main (String [] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        System.out.print("Your number < 100: ");
  6.       int  userInput = scnr.nextInt();
  7.      do {
  8.           System.out.print("Your number < 100: ");
  9.           userInput = scnr.nextInt();
  10.       }while (userInput>=100);
  11.        System.out.println("Your number < 100 is: " + userInput);
  12.        return;
  13.    }
  14. }

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10

7 0
3 years ago
Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output tho
katen-ka-za [31]

Answer:

import java.util.Scanner;

public class BasicInput {

   public static void main(String[] args) {

       //Create an object of the Scanner class

       Scanner scnr = new Scanner(System.in);

       

       //Define int and double variables

       int userInt;

       double userDouble;

       

       //Define char and string variables similarly

       char userChar;

       String userString;

       

       //Prompt the user to enter an integer

      System.out.println("Enter integer:");

       //Store the input in the integer variable

       userInt = scnr.nextInt();

       

       //Prompt the user to enter a double

        System.out.println("Enter double:");

       //Store the input in the double variable

      userDouble = scnr.nextDouble();

       

       //Prompt the user to enter a char

        System.out.println("Enter char:");

       //Store the input in the char variable

      userChar = scnr.next().charAt(0);

       

       //Prompt the user to enter a string

        System.out.println("Enter String:");

       //Store the input in the string variable

      userString = scnr.next();

       

       //Output the four values on a single line

       //separated by a space

       System.out.println(userInt + " " + userDouble + " " + userChar + " " + userString);

       

   }

   

}

Sample Output:

Enter integer:

>>12

Enter double:

>>23

Enter char:

>>s

Enter String:

>>asdasd

12 23.0 s asdasd

Explanation:

The code above has been written in Java. It contains comments explaining every part of the code. Please go through the comments.

5 0
3 years ago
Care should be taken whenever you post comments or photos to any social media or other websites, because each of these online ac
ohaa [14]

Answer:

True is the correct answer for the above question.

Explanation:

  • The social website is used to connect the people using the internet to communicate. With the help of this, any people can communicate within the world's people.
  • If anyone posts their pictures or comment on this type of website, then they need to care for that post or pictures. it means he needs to make decisions to choose the pictures or comments while posting.
  • It is because when the user posts the wrong comments or pictures, then their popularity is less in front of the other people called society.
  • This concept is also said by the question, hence it is a true statement.
5 0
4 years ago
Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
ddd [48]

Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
  14.        listNumber.append(min(listNumber))
  15.    
  16.    print(listNumber)
  17. modifyList([-1,-99,-81])
  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

At last we can print the listNumber (Line 17).

If we test our function using the three sets of input list, we shall get the following results:

[-1, -99, -81, -99]

[1, 99, 8, 99]

[-1, 99, -81]

3 0
3 years ago
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