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Crazy boy [7]
2 years ago
7

What is the value of creating recurring tasks?

Computers and Technology
2 answers:
a_sh-v [17]2 years ago
7 0

Answer:

saves time spent manually creating multiple tasks

Explanation:

it correct on edge 2021

scoundrel [369]2 years ago
4 0

Answer:

✔️saves time spent manually creating multiple tasks

Explanation:

I did it on edge

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if i were to plug this in my ps4 usb port and connect it to the tv would it work please and if so please explain
Brilliant_brown [7]
Probably, most likely yes. this is just basically adding a bit of extra length. the ps4 port goes in the end and the part for the tv acts as a hdmi cord.
4 0
3 years ago
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What age did people set in farming villages
Sveta_85 [38]
As young as 10 years old

have a good day :)

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3 years ago
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True or False. A list can have only the same data type values.
shepuryov [24]

the answer its false.

hope this helps

6 0
3 years ago
A customer bought a goods for Rs.9,000 after getting 10% discount. Calculate the marked price of the goods.Write in Qbasic.​
Darina [25.2K]

Answer:

Rs. 10,000

Explanation:

10% discount means,

customer bought the things at 100% - 10% = 90%

so if 90% --> 9000

1% --> 100

total price = marked price which is 100%

100% ---> 100*100 = Rs. 10,000

7 0
2 years ago
Read 2 more answers
Write a C++ program to calculate the course score of CSC 126. 1. A student can enter scores of 3 quizzes, 2 exams, and a final e
miss Akunina [59]

Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

   double quiz1, quiz2, quiz3, exam1, exam2, finalexam,quiz;

   cout<<"Quiz 1: "; cin>>quiz1;

   cout<<"Quiz 2: "; cin>>quiz2;

   cout<<"Quiz 3: "; cin>>quiz3;

   cout<<"Exam 1: "; cin>>exam1;

   cout<<"Exam 2: "; cin>>exam2;

   cout<<"Final Exam: "; cin>>finalexam;

   if(quiz1<=quiz2 && quiz1 <= quiz3){        quiz=(quiz2+quiz3)/2;    }

   else if(quiz2<=quiz1 && quiz2 <= quiz3){        quiz=(quiz1+quiz3)/2;    }

   else{         quiz=(quiz1+quiz2)/2;     }

   int weight = 0.20 * quiz + 0.30 * ((exam1 + exam2)/2) + 0.50 * finalexam;

   cout<<"Average Weight: "<<weight<<endl;

   if(weight>=91 && weight<=100){        cout<<"Letter Grade: A";    }

   else if(weight>=81 && weight<=90){        cout<<"Letter Grade: B";    }

   else if(weight>=70 && weight<=80){        cout<<"Letter Grade: C";    }

   else{        cout<<"Letter Grade: F";    }

   return 0;

}

Explanation:

See attachment for complete program where comments were used to explain difficult lines

Download cpp
8 0
2 years ago
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