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Crazy boy [7]
3 years ago
7

What is the value of creating recurring tasks?

Computers and Technology
2 answers:
a_sh-v [17]3 years ago
7 0

Answer:

saves time spent manually creating multiple tasks

Explanation:

it correct on edge 2021

scoundrel [369]3 years ago
4 0

Answer:

✔️saves time spent manually creating multiple tasks

Explanation:

I did it on edge

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To someone on the internet or another outside network, it appears that all information is coming from a single computer when ___
aev [14]
Application gateway or application layer gateway
6 0
3 years ago
Create a new Java project/class called Examine1. Prompt user as to how many numbers they would like to enter. Use a cumulative s
Zinaida [17]

Answer:

Explanation:

The following code is written in Java and like requested prompts the user for a number to continue or a letter to exit. Then loops and keeps adding all of the numbers to the sum variable and adding 1 to the count for each number entered. Finally, it prints the sum and the average using printf and the variables.

import java.util.Scanner;

class Examine1 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int sum = 0;

       int count = 0;

       System.out.println("Enter a number to continue or a letter to exit.");

       while(in.hasNextInt()) {

           System.out.println("Enter a number:");

           sum += in.nextInt();

           count += 1;

       }

       System.out.printf("The sum is %s.%n", sum);

       System.out.printf("The average is %s.", (sum / count));

   }

}

8 0
3 years ago
) Consider the array called myArray declared below that contains and negative integers. Write number of positive integers in the
grigory [225]

Answer:

#include <iostream>

using namespace std;

int main()

{

 

  int arr[]={3,-9,9,33,-4,-5, 100,4,-23};

  int pos;

  int n=sizeof(arr)/sizeof(arr[0]);

  for(int i=0;i<n;i++){

      if(arr[i]>=0){

          pos++;

      }

  }

  cout<<"Number of positive integers is "<<pos<<endl;

  return 0;

}

Explanation:

create the main function in the c++ programming and declare the array with the element. Then, store the size of array by using the formula:

int n=sizeof(arr)/sizeof(arr[0]);

after that, take a for loop for traversing the array and then check condition for positive element using if statement,

condition is array element greater than or equal to zero.

if condition true then increment the count by 1.

this process happen until the condition true

and finally print the count.

6 0
3 years ago
PLS HELP MEE!!!
kramer

Answer:

starting with lowercase letters, using uppercase letters for the first letter in a new word

Explanation:

starting with a dollar sign, using lowercase for the remaining parts of each word

4 0
3 years ago
Linux - Ubuntu 16.4:
babymother [125]

I believe you have to install locate with "sudo apt-get install locate" and type "locate 'filename'"

6 0
3 years ago
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