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Dimas [21]
3 years ago
14

PLEASE HELP!!!!!!! I WILL DO BRAINLIEST The angles that share the same tangent value as tan(45°) have terminal sides in quadrant

:
II
III
IV
(none of the quadrants).
Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

The angles that share the same tangent value as of tan 45 degrees would be in Quadrant III. This is because in this quadrant the ratios would equal a positive value, which is the same as in the first quadrant, also positive. Tan 45 = 1.

We would need both the x and the y values be either both positive or negative to get a positive final value.
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jeka57 [31]
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Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
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solve for positive solution of C
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Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
3 years ago
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