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Maslowich
3 years ago
7

Determine whether the ffunction X/(x^2-1) is odd even or neither

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

equation is:

f(x) = \frac{x}{ {x}^{2} - 1 }

so if its even f(-x) should be equal to f(x)

that means

f( - x) =   \frac{ - x}{  {( - x)}^{2}  - 1}  \\  \\ f( - x) =     - \frac{ x}{ {x}^{2}  - 1}

so f(x) is not equal to f(-x) so its not even

If its odd than f(-x) should be equal to -f(x)

- f(x) =  - ( \frac{ x}{ { x}^{2} - 1 } ) \\  - f(x) =    - \frac{ x}{ {x}^{2} - 1 }

so as we can see f(-x)= - f(x)

so the function is odd

Ans:function is odd and not even

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The answer is below

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Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

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Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

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Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

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Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

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Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

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