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Alika [10]
3 years ago
13

Jeanetta collects antique picture frames. In her first year of collecting, she collects 10 frames. Each year, she hopes to colle

ct
three more frames than the previous year. The number of frames Jeanetta will have after 10 years of collecting is represented
by the expression below.
10
2 [10+3(n-1)]
=1
How many frames will Jeanetta have after 10 years of collecting?
•235
•255
•1,640
•1,649
Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:

235

Step-by-step explanation:

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How can i solve that equation
forsale [732]

Answer:

C and E

Step-by-step explanation:

3 \tan( \beta )  = 2.  \:  \:  \:  \:  \tan( \beta )  =  \frac{2}{3}

\frac{h}{x}  =  \tan( \beta )  =  \frac{2}{3}

if \:  \: h = 2 \:  \:  \: x = 3 \:  \:  \: and \:  \:  \: t =  \sqrt{ {h}^{2} + x }

C. t =  \sqrt{13} ✅

○♧○♧○♧○♧○♧○♧○♧○♧○♧○♧○♧○

if \: \: \: h = 4 \:  \:  \:  \: x = 6 \:  \:  \: and \:  \:  \: t =  \sqrt{ {h}^{2}  +  {x}^{2} }

E. t = 2 \sqrt{13} ✅

8 0
3 years ago
Can someone find the initial value for this please
Dimas [21]
Initial value means value at x=0.

from the graph y=-2 at x=0
hence, first option
4 0
4 years ago
Which graphs of functions decrease over part of the domain and increase over the rest of the​ domain? On what open intervals do
Kipish [7]

Answer:

we can identify the period over which the graph is changing in specific way.

we say that function is increasing over an interval if the input values of functions increases within the interval. similarly function is decreasing if its input values decrease within the interval.

5 0
3 years ago
At a party, 75% of the people are adults and 25% are children. What is the simplest ratio of adults to children?
mr_godi [17]

0.3:0.1

Step-by-step explanation:

first convert the % to decimals.

75%=0.75

25%=0.25

then look for a common factor and divide be that, in this case its 5.

0.75/5=0.15

0.25/5=0.5

now since these arent in the simplified form, you gotta divide again by 5.

0.15/5=0.3

0.5/5=0.1

3 0
2 years ago
Solve the following subtraction problems. a. 8 mi. 133 yd. 2 ft. – 5 mi. 107 yd. 2 ft. b. 2 yd. 2 ft. 6 in. – 1 ft. 11 in. c. 6
aksik [14]

Let's keep in mind the conversion factors between mile, yard, feet and inches:

1 mile = 1760 yards

1 yard = 3 feets

1 feet = 12 inches


a) 3 mi. 26 yd.

We have:

8 mi. 133 yd. 2 ft. –

5 mi. 107 yd. 2 ft =

Here, we can simply do the substraction of each term, and we get:

(8-5) mi  (133-107) yd  (2-2) ft =

3 mi. 26 yd  0 ft =

3 mi. 26 yd.


b) 2 yd. 7 in.

We have:

2 yd. 2 ft. 6 in. –

0 yd.  1 ft. 11 in.

Here, we need to convert 1 feet into 12 inches and add them to the inches in the first term as follows:

2 yd. 2 ft. 6 in. = 2 yd. 1 ft. (6+12) in. = 2 yd. 1 ft. 18 in.

So now the subtraction becomes:

2 yd. 1 ft. 18 in. –

0 yd.  1 ft. 11 in.

and now we can simply do the substraction of each term, and we get:

(2-0) yd.  (1-1) ft.  (18-11) in. =

2 yd. 0 ft. 7 in. =

2 yd. 7 in.


c)  5 yd. 5 in.

We have:

6 yd.  0 ft. 0 in. –

0 yd.  2 ft. 7 in.

We have to "move" 1 yard into  feets and inches in the first term, as follows:

6 yd.  0 ft. 0 in. = 5 yd. 3 ft. 0 in. = 5 yd. 2 ft. 12 in.

And now the subtraction becomes:

5 yd. 2 ft. 12 in. -

0 yd.  2 ft. 7 in. =

5 yd.  0 ft. 5 in. =

5 yd. 5 in.


d) 8 in.

We have:

8 yd. 0 ft. 4 in. –

7 yd. 2 ft. 8 in.

Again, let's convert the first term, moving yards into feets and inches:

8 yd. 0 ft. 4 in. = 7 yd. 3 ft. 4 in. = 7 yd. 2 ft. (4+12) in. = 7 yd. 2 ft. 16 in.

So now the subtraction is:

7 yd. 2 ft. 16 in. -

7 yd. 2 ft. 8 in. =

0 yd. 0 ft. 8 in. =

8 in.

3 0
4 years ago
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