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Vera_Pavlovna [14]
2 years ago
12

Y = 4x+1 y=x^2 + 2x - 2 A.6,2 B. 2,6 C. -6,2 D. -6,-2

Mathematics
1 answer:
natta225 [31]2 years ago
7 0

Answer:

The solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

Step-by-step explanation:

Given that

y = 4x + 1  (i)

y = x^2 + 2x -2 (ii)

Now, by susbstituting the value of 'y' from equation i to equation ii, we get

4x+1=x^2 + 2x -2

0=x^2 + 2x -2-4x-1

0=x^2 + (2x -4x) +(-2-1)

0=x^2 + (-2x) +(-3)

0=x^2 -2x -3

x^2 -2x -3 = 0 (iii)

Now by factorization, equation iii can be written as

x^2 -3x +x -3 = 0

x(x -3) + 1(x -3) = 0

(x -3)(x +1) = 0

x = 3 and x = -1

By putting the values of x in equation i, we get

y = 4(3) + 1

y = 12 +1

y = 13

and

y = 4(-1) + 1

y = -4 +1

y = -3

Therefore, the solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

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