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densk [106]
2 years ago
15

Y varies directly as the square of x. If y is 25 when x is 3 find y when x is 2

Mathematics
1 answer:
Vilka [71]2 years ago
8 0

Answer:

y = \frac{100}{9}

Step-by-step explanation:

given y varies as the square of x then the equation relating them is

y = kx² ← k is the constant of variation

to find k use the given condition y = 25 when x = 3

k = \frac{y}{x^{2} } = \frac{25}{9}

⇒ y = \frac{25}{9} x²

when x = 2

y = \frac{25}{9} × 4 = \frac{100}{9}



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<u>Answer:</u>

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<u>Step-by-step explanation:</u>

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Therefore, the first five terms of the sequence defined by the explicit formula a_n=21-2n^2 are 19, 13, 3, -11, -29.


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