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3 years ago

5

Can anyone figure this out???

2 answers:

Anestetic [448]3 years ago

5 0

It’s a right triangle because it has a 90 degree angle

lukranit [14]3 years ago

5 0

Your answer would be a right triangle, because in the corner there is a 90° angle .

Hope helps-Aparri

Please rate my answer. Thank you!

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In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?

valina [46]

To solve this problem, we need to know that
arc length = r θ where θ is the central angle in radians.

We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3

Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees

8 0

3 years ago

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HELP !!!!!!!!!!!!!!!!!!!!!!!

Lelu [443]

Answer:

25 $\pi$ Or 78.5 units³

Step-by-step explanation:

1/3πr²h

1/3xπx25x3=25π or 78.5

7 0

3 years ago

Read 2 more answers

Given below are descriptions of two lines.

gulaghasi [49]

Answer:

Line 1 is 1/3

Line 2 is 1/3 as well

Choice 1

Step-by-step explanation:

<u>Rise over run</u>

<em><u>Line 1:</u></em>

$\frac{(7)-(3)}{(6)-(-6)}$

$\frac{4}{12}$

<u>Simplify:</u>

1/3

<em><u>Line 2:</u></em>

$\frac{(2)-(1)}{(-3)-(-6)}$

$\frac{1}{3}$

1/3

1 is Paralell to 2 because they have the same slope

I hope this helps! :D

Pls give thx and brainliest if i’m right!

5 0

3 years ago

Helppppppppppppppppppp helppppppppppppp

Annette [7]

<h2>•5×7^2</h2>

<em>HOPE</em><em> </em><em>ITS</em><em> </em><em>HELPFUL</em><em> </em>^_^

<h2>•RHONA</h2>

3 0

3 years ago

What is the mass of a cylinder of lead with a radius of 2 centimeters and a height of 6 centimeters, given that the density of l

ycow [4]

The mass of lead cylinder is: 859.10 grams

Step-by-step explanation:

In order to find the mass of a cylinder we have to find the volume first

Given

Radius = r = 2 cm

Height = h = 6 cm

The volume of cylinder is given by:

$V = \pi r^2h$

Putting the values

$V = 3.14 * (2)^2 * 6\\= 3.14*4*6\\=75.36\ cm^3$

Now,

Density of lead per cm^3 = 11.4g

$Mass\ of\ cylinder = Volume*Density\\= 75.36*11.4\\=859.10\ grams$

The mass of lead cylinder is: 859.10 grams

Keywords: Volume, Density

Learn more about volume at:

#LearnwithBrainly

7 0

3 years ago