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2 years ago

Use powers to rewrite these problems: Example: 5 x 5 = 52

Mathematics

1 answer:

jeyben [28]2 years ago

5 0

Answer:

Problem A

5 * 5 * x * x * x

$5^2*x^3$

Problem B

8 * 8 * 8

$8^3$

Problem C

4 * 4 * 4 * x * x * x * x

$4^3*x^4$

You might be interested in

7a +42 +8< -10 + 9a -64a

Mamont248 [21]

Answer:

a < -30/31

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

7a + 42 + 8 < -10 + 9a - 64a

Step 2: Solve for a

Combine like terms (a): 7a + 42 + 8 < -10 - 55a
Combine like terms: 7a + 50 < -10 - 55a
[Addition Property of Equality] Add 55a on both sides: 62a + 50 < -10
[Subtraction Property of Equality] Subtract 50 on both sides: 62a < -60
[Division Property of Equality] Divide 62 on both sides: a < -30/31

Here we see any number a less than -30/31 would work as a solution to the inequality.

3 0

2 years ago

What is the sum of -3 and -12

goblinko [34]

Answer:

-15

Step-by-step explanation:

-3 + -12 = -15

4 0

3 years ago

What is the perimeter of the rectangle? one side is 6in. and the A=30 sq in.

monitta

The perimeter of a rectangle can be found by dividing the area by one side.
30/6=5
Then, add the sides up and you get the perimeter.
5+5+6+6=22

The answer is 22 inches.

3 0

3 years ago

Read 2 more answers

According to a recent publication, the mean price of new mobile homes is $63 comma 800. Assume a standard deviation of $7900.

wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,580, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,117, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}$

For n=25 we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580$

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117$

4 0

3 years ago

A farmer planned to plant 120 seeds in all. After planting 10 more seeds each day than was planned, she was able to finish 2 day

zheka24 [161]

Let s=number of seeds and t=number of days...

st=120 and (s+10)(t-2)=120

From the first we can say t=120/s, now using this value of t in the second equation gives us:

(s+10)(120/s-2)=120

(s+10)(120-2s)/s=120

(s+10)(120-2s)=120s

120s-2s^2+1200-20s=120s

2s^2+20s-1200=0

s^2+10s-600=0

(s+30)(s-20)=0, since s>0

s=20, and since she planted s+10 seeds per day to finish two days earlier:

20+10=30

She planted 30 seeds per day.

3 0

3 years ago