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s2008m [1.1K]
2 years ago
11

Last year 85 students in 7th grade This school year only 68 What is the percent decrease?

Mathematics
1 answer:
klemol [59]2 years ago
4 0

Answer: 11.11%

17:153*100 =

(17*100):153 =

1700:153 = 11.11

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PLEASE HELP QUICK!!!!!!1
Lana71 [14]

volume of pyramid = 1/3(area of the base)(height)

volume = 1/3(8x6)(9) = 3x48 = 144 in^3

answer: 144 in^3

4 0
3 years ago
Read 2 more answers
Write a polynomial that represents the shaded area of the figure below
IRISSAK [1]
I hope this helps you

8 0
3 years ago
A certain car rental location charges a daily fee as well as a mileage charge. On one trip a businessman rented a car for the da
nikklg [1K]

Answer:

x\approx 267\ miles

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

f(x)=mx+b

For the problem at hand, we must pick the adequate variables according to the data provided.

The question states the charge for renting a car is a function of the mileage. It also provides two points from which we can build our model. Let's set the following variables:

c = the charge for renting a car in dollars

x = the distance driven by the businessman in miles

Representing the ordered pair as (x,c), we have the points: (150,79) and (65,63.70). Our model will be expressed as:

c = mx+b

We must find the values of m and b with the data provided. Substituting the first point:

79 = 150m+b

Substituting the second point:

63.70 = 65m+b

Both equations form the following system:

\left\{\begin{matrix}150m+b=79\\ 65m+b=63.70 \end{matrix}\right.

Subtracting both equations:

150m-65m=79-63.70

Note the variable b was canceled out in the operation, leaving only the variable m to solve. Joining like terms:

85m=15.3

Solving:

m=15.3/85=0.18

From the first equation

79 = 150m+b

Solving for b:

b=79-150m=79-150(0.18) = 52.

The model for the problem is:

c=0.18x+52

Now we need to calculate how many miles (x) could be driven for c=$100. From the equation above, substitute c=100

100=0.18x+52

Solve for x:

0.18x+52=100

0.18x=100-52=48

x=48/0.18=266.67

Rounding to the closest integer:

\boxed{x\approx 267\ miles}

7 0
3 years ago
Seventh grade
alexandr402 [8]

Answer:

$690.86

Step-by-step explanation:

100% from the original cost is: 2 x 863.57 = $1,727.14

40/100 = X/1727.14 (40 percent is what of 1,727.40) (%/100 = is/of)

(40 * 1,727.14) / 100 = $ 690.86

6 0
2 years ago
A 15 pound bag of ice costs $ 1.80. Give the unit rate.
Vaselesa [24]
We can use a rule of three simple, direct proportion to solve this problem.
15 pounds correspond to $1.80, then the question is to find the price of one pound, the called unit rate. We state the rule of three:
15 pound ---->  $1.80
 1 pound -----> x
x = (1)(1.80)/15
x = 0.12
Therefore, each pound costs $0.12 that is the unit rate in pounds
7 0
3 years ago
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