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2 years ago

12

in a random sample 20 of 200 students prefer apples for a snack. based on the sample about how many apples should the teachers b

uy for a snack of 4000 students?

1 answer:

ludmilkaskok [199]2 years ago

6 0

20/200 is only 10%, 10% of 4000 is 400.

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Eighteen divided by the sum of two and seven <br> Numerical expression.

Alchen [17]

Answer:

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Step-by-step explanation:

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3 years ago

According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?

bogdanovich [222]

Answer:

Seven-thirds

Step-by-step explanation:

The give equation is $f(x)=9x^8+9x^6-12x+7$ .

The leading coefficient is 9

The constant term is 7

According to the rational root theorem, the ratio of factors the constant terms to that of the coefficient of the leading term are all possible rational roots of the given polynomial.

Base on this theorem, $\frac{7}{3}$ or seven thirds is a potential root because the numeration is a factor of 7 and the denominator is a factor of 9.

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3 years ago

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Find all points (x, y) on f(x) = X^3 – 4x + 3 where the slope of the tangent line is 8.

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3 years ago

Which correctly uses bar notation to represent the repeating decimal

ioda

Answer:

2nd one..

Step-by-step explanation:

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3 years ago

What are the roots of the polynomial equation x cubed minus 5 x + 5 = 2 x squared minus 5?

Dennis_Churaev [7]

Roots of the polynomial $x^3-5x+5=2x^2-5$ are $x=\sqrt{5},x=-\sqrt{5}\,\,and\,\,x=2$

Step-by-step explanation:

We need to find roots of the polynomial equation: $x^3-5x+5=2x^2-5$

Solving the polynomial to find roots:

$x^3-5x+5=2x^2-5\\Rearranging:\\x^3-5x+5-2x^2+5=0\\x^3-2x^2-5x+10=0$

Finding factors by grouping:

$(x^3-2x^2)(-5x+10)=0\\Finding\,\,common\,\,terms:\\x^2(x-2)-5(x-2)=0\\(x^2-5)(x-2)=0\\x^2-5=0\,\,and\,\,x-2=0\\x^2=5\,\,and\,\,x=2\\x=\pm \sqrt{5}\,\,and\,\,x=2$

So, roots of the polynomial $x^3-5x+5=2x^2-5$ are $x=\sqrt{5},x=-\sqrt{5}\,\,and\,\,x=2$

Keywords: Roots of Polynomial

Learn more about Roots of Polynomial at:

#learnwithBrainly

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3 years ago