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velikii [3]
3 years ago
10

What is the value of 6/(2)-3

Mathematics
2 answers:
kati45 [8]3 years ago
8 0

Answer:

0

Step-by-step explanation:

\frac{6}{2} -3 = 3 - 3 = 0

sveta [45]3 years ago
7 0
To subtract the two numbers, make sure both integers have the same denominators. -3 is equal to -6/2. (6/2)-(6/2) = 0. The answer is 0.
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I dont know. Help?<br> Please and Thanks
a_sh-v [17]

Answer:

Y' (5, -3), Z' (3, -2)

Step-by-step explanation:

The translation is right 4 and down 1.  Since you are going from (3, -4) to (7, -5), to get from 3 to 7 on the x axis you move right 4. To get from -4 to -5 on the y axis, you go down 1.

Y (1, -2) add 4 to the x value. 1 + 4 = 5.  Add -1 to the y value. -2 + -1 = -3. Y' (5, -3)

Z (-1, -1). Add 4 to the x value. 4 + (-1) = 3.  Add -1 to the y value. -1 + (-1) = -2.

4 0
3 years ago
Find the perimeter of the polygon with vertices A(-6,-4), B(-3,6), C(4,0), and D(2,-1)?
EleoNora [17]
Check the picture below.

so the perimeter of the polygon is the sum of all its sides, namely, AB + BC + CD + DA.

now, let's check how long each side is,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~{{ -6}} &,&{{ -4}}~) &#10;%  (c,d)&#10;&B&(~{{ -3}} &,&{{ 6}}~)&#10;\end{array}&#10;\\\\\\&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\&#10;-------------------------------\\\\&#10;AB=\sqrt{[-3-(-6)]^2+[6-(-4)]^2}&#10;\\\\\\&#10;AB=\sqrt{(-3+6)^2+(6+4)^2}&#10;\\\\\\&#10;AB=\sqrt{3^2+10^2}\implies \boxed{AB=\sqrt{109}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&B&(~{{ -3}} &,&{{6}}~) &#10;%  (c,d)&#10;&C&(~{{ 4}} &,&{{ 0}}~)&#10;\end{array}&#10;\\\\&#10;-------------------------------\\\\&#10;BC=\sqrt{[4-(-3)]^2+[0-6]^2}\implies BC=\sqrt{(4+3)^2+(0-6)^2}&#10;\\\\\\&#10;BC=\sqrt{7^2+(-6)^2}\implies \boxed{BC=\sqrt{85}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&C&(~{{ 4}} &,&{{0}}~) &#10;%  (c,d)&#10;&D&(~{{ 2}} &,&{{ -1}}~)&#10;\end{array}&#10;\\\\&#10;-------------------------------\\\\&#10;CD=\sqrt{(2-4)^2+(-1-0)^2}\implies CD=\sqrt{(-2)^2+(-1)^2}&#10;\\\\\\&#10;\boxed{CD=\sqrt{5}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&D(~{{ 2}} &,&{{-1}}~) &#10;%  (c,d)&#10;&A&(~{{ -6}} &,&{{ -4}}~)&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;DA=\sqrt{[-6-2]^2+[-4-(-1)]^2}\\\\\\ DA=\sqrt{(-6-2)^2+(-4+1)^2}&#10;\\\\\\&#10;DA=\sqrt{(-8)^2+(-3)^2}\implies \boxed{DA=\sqrt{73}}

sum those sides up, and that's the perimeter of the polygon.

6 0
3 years ago
Two feet is what percent of one yard
Mashcka [7]
1 yard = 3 feet
2 feet = 2/3 of 1 yard

If you can't figure it out from there, and if you want to get really specific, it's <span>66.67%</span>
3 0
3 years ago
A month is randomly chosen. what is the probability that the month chosen has less than 31 days?
Pepsi [2]

There are 4 months that are 30 days long and 7 months that are 31 days long.

So therefore the probability the the month chosen has less than 32 days is: 7/12. 7 out of 12 months
8 0
3 years ago
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Ryan bought a calculator for $200 he resold it and made a profit of 25% how much did he sell the calculator for?
vladimir1956 [14]
He sold the calculator for $250
5 0
4 years ago
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