Answer:
Total number of puppies in the litter = 11
Step-by-step explanation:
Let the number of yellow puppies in the litter = y
And the number of black puppies in the litter = b
If there was one less black puppy, ratio of yellow to black puppies = 
2(b - 1) = 3y
3y - 2b = -2 -----(1)
If there was one more black puppy, ratio of yellow puppies to black puppies = 
2y = b + 1
2y - b = 1 -------(2)
Equation (1) - 2× equation (2)
(3y - 2b) - 2(2y - b) = -2 - 2
3y - 4y - 2b + 2b = -4
y = 4
From equation (1),
3×4 - 2b = -2
12 - 2b = -2
-2b = -14
b = 7
Total number of puppies in the litter = 7 + 4 = 11
Answer:
86.40
Step-by-step explanation:
First you do 80 x 0.08 to get 6.4, then you add that to 80 to get 86.40 dollars
I did this in school: it would be A, C, and D
(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.
