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3 years ago

What is the value of X?

Mathematics

1 answer:

LenKa [72]3 years ago

7 0

Answer:

5.625 or 5-5/8 or 45/8

Step-by-step explanation:

Solve using Similar triangles again

ratio of 4:7.5

3/x=4/7.5 cross multiply

22.5=4x

x=22.5/4=5.625=5-5/8=45/8

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Find the midpoint of PQ. P(-2, 3) and Q (4, 5)

Aleks [24]

Answer: (1, 4)

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2})$

Substitute in the values for $(x_1,y_1)$ and $(x_2,y_2)$

$(\frac{(-2+4)}{2},\frac{(3+5)}{2})$

Add − 2 and 4

$(\frac{(2)}{2},\frac{(3+5)}{2})$

Divide 2 by 2

$(1,\frac{(3+5)}{2})$

Add 3 and 5

$(1,\frac{(8)}{2})$

Divide 8 by 2 .

Answer: (1, 4)

7 0

4 years ago

Thank you please show work if you can<3!!!!! x= y=

otez555 [7]

4 + 2x - 7 = 12

2x - 7 + 4 = 12

2x -3 = 12

2x = 15

x = 7.5

2x - 7 = 7.5 - 7 = 0.5

PLS MARK BRAINLIEST

3 0

3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

How do you write out 3 1/4 times 24

solmaris [256]

The answer is 28 because 1/4 is equivalent to .25 so 3.25 x 24 equals 28.

4 0

3 years ago

Um número é o quíntuplo do outro e a soma dos dois é 54. De acordo com essas informações, podemos afirmar que a diferença entre

NNADVOKAT [17]

Answer:

Step-by-step explanation:

A partir das informações fornecidas, as seguintes equações podem ser modeladas:

$X=5Y\\X+Y=54\\$

Resolvendo o sistema:

$Y+5Y=54\\Y=9\\X=9*5=45$

A diferença entre eles é:

$X-Y=45-9\\X-Y=36$

A diferença entre o maior número e o menor número é 36.

7 0

3 years ago