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Luden [163]
2 years ago
13

In the figure, PQ is parallel to RS. The legth of RP is 4 cm; the length of PT is 16 cm; the length of QT is 20 cm. What is the

length of SQ?

Mathematics
2 answers:
Studentka2010 [4]2 years ago
6 0
4/16  = SQ/20

SQ = (4*20) / 16  = 5 cm
gladu [14]2 years ago
3 0

Answer:

<h2>A. 5 cm.</h2>

Step-by-step explanation:

Givens

PQ \parallel RS

RP=4cm

PT=16cm

QT=20cm

Now, you can observe that the problem is about propotions, because we have two transversals crossing a pair of parallels. Here we can build the following proportion.

\frac{SQ}{RP} =\frac{QT}{PT}

Replacing all given values, we have

\frac{SQ}{4} =\frac{20}{16}\\SQ=\frac{20}{16} \times 4\\ SQ=5

Therefore, the length of SQ is 5 centimeters. The right answer is A.

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In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s
Oksi-84 [34.3K]

Answer:

a) \mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

b) From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

c) P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

P(Z\geq2.070)=1-P(Z

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

8 0
3 years ago
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
If you answer i'll give brainllest
GalinKa [24]

Answer:

the first one but make sure to divide

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
A cone has a diameter of 24 in. and a height of 10 in. What is the volume of the cone? Use 3.14 as an approximation for straight
pashok25 [27]
The volume of the cone is 1507.96. Hope this helps!! Have an amazing rest of your day!! :)
4 0
3 years ago
Read 2 more answers
Does anyone know how to solve this? :(
rosijanka [135]

Answer:

i dont know but my Friends do

4 0
2 years ago
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