3 years ago

A teacher has 27 students in her class she ask the students to form as many grips of 4 how many students will not be in a group

1 answer:

4 0

There will be 6 groups of 4 so only 3 people won't be in a group

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Bad White [126]

I'll use arithmetic series to find it.

First two-digit number divisible by 3 is 12, last such number is 99. Every 3rd number is divisible by 3.

So,

$a_1=12\\a_n=99\\d=3\\n=?\\\\a_n=a_1+(n-1)\cdot d\\99=12+(n-1)\cdot 3\\3n-3=87\\3n=90\\n=30$

There are 30 such numbers.

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3 years ago