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Phantasy [73]
3 years ago
7

Do you know the answer

Mathematics
1 answer:
aivan3 [116]3 years ago
3 0

Answer:

84.3

Step-by-step explanation:

use this equation



You might be interested in
Find sin0, cos0, tan0
djverab [1.8K]

Answer:

sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5

Step-by-step explanation:

We need to find sine, cosine, and tangent of theta for this triangle.

First, define the different trigonometric functions:

- sine is opposite side to the angle divided by the hypotenuse (longest side not adjacent to the 90 degree angle)

- cosine is the adjacent side next to the angle divided by the hypotenuse

- tangent is the opposite side to the angle divided by the adjacent side

Now, look at theta (θ):

- the opposite side is marked 12

- the adjacent side is marked 5

- the hypotenuse is marked 13

So:

- sin(θ) = opposite / hypotenuse = 12/13

- cos(θ) = adjacent / hypotenuse = 5/13

- tan(θ) = opposite / adjacent = 12/5

Thus the answers are: sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5.

6 0
3 years ago
Read 2 more answers
(19pts) please help me with these 2 problems !?
SSSSS [86.1K]

1. linear function

Since it goes on in a constant rate

2.y=x^{3}

Since as x goes up by one y is x to the power of 3.

5 0
3 years ago
9. What is 36:39 in simplest form?<br> O A. 1:3<br> OB. 12:13<br> O C. 13:12<br> D. 36:39
bazaltina [42]

Answer:

B

Step-by-step explanation:

36/3 = 12

39/3 = 13

12:13

3 0
3 years ago
The tape diagram represents an equation.
Orlov [11]

Answer:

t = 4

Step-by-step explanation:

13 + t = 17

t = 4

13 + 4 = 17

An easier way to solve a question like this is to subtract the number given by the answer.

Example:

17 - 13 = 4

4 0
3 years ago
In a recent year, the ACT scores for the math portion of the test were normally distributed, with a mean of 21.1 and a standard
Natali5045456 [20]

Answer:

a) P(X

And we can find this probability using the normal standard table or excel:

P(z

b) P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

c) P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

d) We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(21.1,5.3)  

Where \mu=21.1 and \sigma=5.3

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Part b

P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

Part c

P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

Part d

We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

6 0
3 years ago
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