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3 years ago

Evaluate 1/6 + 2/3. a.1/5 b.3/18 c.5/6 d.1 1/6

Mathematics

1 answer:

Delicious77 [7]3 years ago

4 0

Answer:

5/6

Step-by-step explanation:

1/6 + 2/3

We need to get a common denominator of 6

1/6 + 2/3 *2/2

1/6 + 4/6

5/6

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Evaluate 4b-a when a=12 and b=7

Ilia_Sergeevich [38]

Answer:

4b - a = 15

Step-by-step explanation:

if you replace the variables with their equivalent counterparts you get the equation 4(7) - 12 = __ when you do the math make sure to do the parentheses first then subtract, just like in elementary school remember pemdas parentheses, exponents, multiplication, division, addition, subtraction. I hope this helps.

good luck:)

Brainliestttt Plssssssss:)

4 0

3 years ago

Read 2 more answers

Determine the area of the given region under the curve (1/x^4) [1,2]

Nikolay [14]

Answer:

$\displaystyle \frac{7}{24}$

General Formulas and Concepts:

Algebra I

Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

[Area] Limits of Riemann's Sums - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Step-by-step explanation:

Step 1: Define

$\displaystyle f(x) = \frac{1}{x^4} \\ \ [1, 2]$

Step 2: Find Area

[Integral] Set up area: $\displaystyle \int\limits^2_1 {\frac{1}{x^4}} \, dx$
[Integral] Rewrite: $\displaystyle \int\limits^2_1 {x^{-4}} \, dx$
[Integral] Reverse Power Rule: $\displaystyle \frac{-1}{3x^3} \bigg| \limits^2_1$
[Area] Fundamental Theorem of Calculus: $\displaystyle \frac{7}{24}$

Topic: Calculus

Unit: Basic Integration/Riemann Sums

Book: College Calculus 10e

6 0

2 years ago

A little help would be great...

Readme [11.4K]

Answer:

1. The answer is 89

2. 1,7,4,11,4,9,5,1

3. i have no idea sorry

Step-by-step explanation:

7 0

3 years ago

Students from Williams Middle School are also recycling aluminum cans. The data for the numbers of cans brought in each school d

geniusboy [140]

Answer:

The median would be 18,not enough info for the Interquartile range, and range is 10 to 28

Step-by-step explanation:

You all ready said the answers but, the interquartile range.

6 1

3 years ago

Read 2 more answers

Solve for 2 unknowns : 3a+4b=9 ; 2a+2b=6

BARSIC [14]

Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
= 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.

3 0

3 years ago