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2 years ago

Show me a number line

Mathematics

2 answers:

Valentin [98]2 years ago

8 0

Answer:

___________

1 2 3 4 5 6 7 8

Step-by-step explanation:

stepan [7]2 years ago

3 0

A number line looks like this:

——————————
1 2 3 4 5 6 7 8 9 10 .... etc

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The following table shows a portion of a four-year amortization schedule. A 4-year amortization schedule. The loan amount or pri

yKpoI14uk [10]

Answer:

Option c. $ 9,543.97

Explanation:

The row for month 25 shows that after twenty-five payments the balance of the loan is $10,356.03

You are told that the loan amount or principal is $ 19,900.

From those two data, you can calculate how much of the principal has been paid off after 25 months, because the amount paid off is equal to the loan less the balance after 25 payments:

Principal paid off = $ 19,900 - $ 10,356.03 = $9,543.97

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3 years ago

Why does the formula for the number of hosts per subnet (2h – 2) require the subtraction of two hosts?

sineoko [7]

The term of humanism has been very different back during reinasance humanism and modern humanism.
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2 years ago

K/8=11 Find the value of K

____ [38]

Answer:

k=88

Step-by-step explanation:

as 8*11=88

4 0

2 years ago

Read 2 more answers

HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Doss [256]

Answer:

Step-by-step explanation:

Start is at 9 gallons

6 days of water use

9/6 is 1.5

1.5 gallon per day :)

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2 years ago

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
x to the one twelfth power = $x ^{1/12}$

The quantity of x to the one third power, over x to the one twelfth power is:
 $\frac{x ^{1/3}}{x ^{1/12}}$

Since $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

The thirty second root of the quantity of x times x to the second times x to the fifth is
 $\sqrt[32]{x* x^{2} * x^{5} }$

Since $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago