Answer:
<em>There are approximately 114 rabbits in the year 10</em>
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:
Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
We are given two measurements of the population of rabbits on an island.
In year 1, there are 50 rabbits. This is the point (1,50)
In year 5, there are 72 rabbits. This is the point (5,72)
Substituting in the general model, we have:
![50=P_o(1+r)\qquad\qquad[1]](https://tex.z-dn.net/?f=50%3DP_o%281%2Br%29%5Cqquad%5Cqquad%5B1%5D)
![72=P_o(1+r)^5\qquad\qquad[2]](https://tex.z-dn.net/?f=72%3DP_o%281%2Br%29%5E5%5Cqquad%5Cqquad%5B2%5D)
Dividing [2] by [1]:
Solving for r:
![\displaystyle r=\sqrt[4]{\frac{72}{50}}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B72%7D%7B50%7D%7D-1)
Calculating:
r=0.095445
From [1], solve for Po:
The model can be written now as:
In year t=10, the population of rabbits is:
P = 113.6
There are approximately 114 rabbits in the year 10
2.5 pounds or exact fraction 5/2 or 2 1/2 if you want a mixed fraction
La solución del sistema de ecuaciones es igual a (x, y) = (308/47, 42/47).
<h3>¿Cómo resolver un sistema de ecuaciones linear por igualación?</h3>
Los sistemas de ecuaciones basadas en entidades algebraicas se resuelven mediante procedimientos algebraicos. Grosso modo, el método de resolución por igualación consiste en despejar una variable en dos ecuaciones del sistema para eliminarla y reducir el número de ecuaciones <em>lineales</em> y el número de variables.
A continuación, presentamos una aplicación del método de eliminación:
y = 42/47
x = 308/47
La solución del sistema de ecuaciones es igual a (x, y) = (308/47, 42/47).
Para aprender más sobre los sistemas de ecuaciones: brainly.com/question/15811265
#SPJ1
Answer: B
Step-by-step explanation:
Answer:
Answer below, however this question is worded weirdly
Step-by-step explanation:
x(x - 0.37 ) = 12.6
simplify the equation
x^2 - 0.37x = 12.6
x^2 - 0.37x - 12.6 = 0
