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3 years ago

11

Javier has a model of a cone with a radius of 3 inches and a height of 10 inches. Javier increased his model’s volume by doublin

g its radius and height. What is the volume of the larger cone in cubic inches?

2 answers:

yan [13]3 years ago

8 0

Answer:

240 pi in. ^2

Step-by-step explanation:

Just took the test. Correct me if I'm wrong!

Thank you

Tisa B Sora

statuscvo [17]3 years ago

3 0

Answer:

$240 \pi\ in^{3}$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z------> the scale factor

x-----> the volume of the larger cone

y-----> the volume of the original cone

$z^{3}=\frac{x}{y}$

In this problem we have

$z=2$ -----> scale factor

substitute

$2^{3}=\frac{x}{y}$

$8=\frac{x}{y}$

$x=8y$

That means-----> The volume of the larger cone is 8 times the volume of the original cone

Find the volume of the original cone

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=3\ in$

$h=10\ in$

substitute

$V=\frac{1}{3}\pi (3^{2})(10)=30 \pi\ in^{3}$

therefore

The volume of the larger cone is equal to

$8*30 \pi\ in^{3}=240 \pi\ in^{3}$

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Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

<em /> $L \to$ <em> Letters</em>

<em /> $C \to$ <em> Cost</em>

<em />

Using proportional reasoning, we have:

$C = kL$

Where

<em /> $k \to$ <em> ratio of proportion</em>

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

<u>When C = 6.75, we have:</u>

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

<u>When L = 7, we have:</u>

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

<u>When L = 1, we have:</u>

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

<u>When L = 500, we have:</u>

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

<u>When C = 18.90, we have:</u>

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Read more about proportions at:

brainly.com/question/21126582

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3 years ago

Consider the inequality x > - 1.5. determine whether each value of x makes this inequality true

musickatia [10]

9514 1404 393

Answer:

no, yes, yes, no, yes

Step-by-step explanation:

You're looking for values greater than -1.5. All positive numbers will be greater than any negative number.

The two negative numbers among the answer choices are both to the left of -1.5 on the number line. They are less than -1.5, so are <em>not</em> greater than -1.5.

The negative numbers are No; the positive numbers are Yes.

4 0

3 years ago

What us 16.1 across the y-axis

andrey2020 [161]

Answer:

-16.1

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3 years ago

One the first day of school, each student is given $0.50 to attend. On day two, each student earns $1.00, day 3, $2.00, etc. How

aalyn [17]

Answer:

They earn $256 on the ninth day of school.

Step-by-step explanation:

A geometric sequence(in which each term is the previous term multiplied by the ratio) has the following format:

$a_{n+1} = r \times a_{n}$

In which r is the common ratio.

We can also find the nth term as a function of the first term, by the following equation:

$a_{n} = a_{1} \times r^{n}$

In which

$r = \frac{a_{n+1}}{a_{n}}$

In this question:

On the first day, $0.50. So $a_{1} = 0.5$ .

Day two $1.00, day three $2.00.

So

$r = \frac{1}{0.5} = \frac{2}{1} = 2$

Then

$a_{n} = 0.5 \times 2^{n}$

How much do students earn on the ninth day of school?

$a_{9} = 0.5 \times 2^{9} = 256$

They earn $256 on the ninth day of school.

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3 years ago

What is the 10th term in the pattern with the formula 10n – 8?

Nimfa-mama [501]

(10*10) - 8 = 92
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4 years ago