Ask question

Ask question

All categories

3 years ago

10

A standard deck of 52 cards contain four suits clubs spades hearts and diamonds . Each deck contains and equal number of cards i

n each suit. Rochelle chooses a card from the deck records the suit and replaces the card

1 answer:

Kazeer [188]3 years ago

8 0

Answer:

Step-by-step explanation:

I do not know what you mean. What is the question?

You might be interested in

Find the measure of each angle in the triangle.

makvit [3.9K]

<A +<B + < C =180° ==>(5x+6) + (2x+1) + (6x+4) = 180°
13x = 180°-11° ==> 13x 169° and x =169/13 =13°

8 0

3 years ago

Question is in image please help<br> I will give Brainliest :)

lara31 [8.8K]

Answer:

D;the last answer

Step-by-step explanation:

The more negative a fraction or decimal, the lower that actual value.

Therefore since -1 1/5 is the lowest it should go first, and D is the only answer like this! Hope this helps ^^

8 0

1 year ago

Read 2 more answers

The chart shows Maria's workout schedule. Today she worked out with weights and then had a long run. When is the next time Maria

Contact [7]

Answer:

The answer is 15.

Step-by-step explanation:

3 Times 5 equals 15.

5 0

2 years ago

Read 2 more answers

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$

3 0

3 years ago

Which answer best describes the shape of this distribution

Vitek1552 [10]

I think it is C.Skewed right.

5 0

3 years ago

Read 2 more answers