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3 years ago

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A standard deck of 52 cards contain four suits clubs spades hearts and diamonds . Each deck contains and equal number of cards i

n each suit. Rochelle chooses a card from the deck records the suit and replaces the card

1 answer:

Kazeer [188]3 years ago

8 0

Answer:

Step-by-step explanation:

I do not know what you mean. What is the question?

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The equations below represent the numbers y of tickets sold after x weeks for two different local music festivals.

kiruha [24]

Answer:

Part a) 3.5 weeks

Part b) 185 tickets

Step-by-step explanation:

Part a) After how much time have the same number of tickets been sold for both festivals?

Let

x -----> the number of weeks

y ----> the number of tickets sold

we have

<em>Country Music Festival</em>

$y=10x+150$ ----> equation A

<em>Pop Music Festival</em>

$y=20x+115$ ----> equation B

Equate equation A and equation B

$20x+115=10x+150$

solve for x

$20x-10x=150-115$

$10x=35$

$x=3.5\ weeks$

Part b) What is the number of tickets sold at that time?

substitute the value of x=3.5 weeks in the linear equation A or linear equation B

$y=10(3.5)+150$

$y=35+150$

$y=185\ tickets$

6 0

2 years ago

Please help and stop with the links!

ira [324]

It C)
This is because the sum of the two smaller sides in a triangle has to be larger than the bigger sides. 10+12=22.
22 is smaller than 24 which is the third side this no triangle is formed

5 0

2 years ago

A length of rope is stretch between the top edge of the building at stake in the ground the head of the state is at ground level

amid [387]

Because the tree is the halfway point, the building would be twice as tall:

The building is 38 x 2 = 76 feet tall.

3 0

2 years ago

Read 2 more answers

Given h(x) = -5x + 3, find h(5).

cluponka [151]

Answer:

h(5) = -22

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

h(x) = -5x + 3

h(5) is x = 5

<u>Step 2: Evaluate</u>

Substitute in <em>x</em> [Function]: h(5) = -5(5) + 3
Multiply: h(5) = -25 + 3
Add: h(5) = -22

8 0

2 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

2 years ago