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AnnZ [28]
3 years ago
10

In the figure, the segment is parallel to one side of the triangle. The ratio of x to 16 is

Mathematics
1 answer:
Romashka [77]3 years ago
3 0

Answer:

Step-by-step explanatiog:

En la figura anterior, el segmento BC es paralelo al segmento AD. El área trapezoidal ABCD, en centímetros cuadrados, es

que sabemos que el

área del trapezoide = (1/2) * [(BC + AD) * AB]

BC = 8 cm

AD = 12 cm

AB = 2 cm,

entonces el

área del trapezoide = ( 1/2) * [(8 + 12) * 2] -------> 20 cm²

la respuesta es

20 cm²

la respuesta en español

Sabemos que

area del trapecio = (1/2) * [(BC + AD ) * AB]

BC = 8 cm

AD = 12 cm

AB = 2 cm

área del trapecio = (1/2) * [(8 + 12) * 2] -------> 20 cm²

La respuesta es

20 cm²

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Answer:

\boxed{x=9}\\\boxed{z=76}

Step-by-step explanation:

Hello There!

<u>Geometry</u>

The angles shown represented by the expressions (11x + 5) and (5x+59) are vertical angles

Vertical angles are congruent so we can use this equation to solve for x

<u>Basic Algebra</u>

11x + 5 = 5x + 59

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Answer:

1) The simplified radical form is  \sqrt{36x^2}=6x

2) The simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) The simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) The simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

Step-by-step explanation:

1) Given expression is \sqrt{36x^2}

To find the simplified radical form of the given expression :

\sqrt{36x^2}

=\sqrt{36\times x^2}

=\sqrt{36}\times \sqrt{x^2}

=\sqrt{6\times 6}\times \sqrt{x\times x}

=6\times x

\sqrt{36x^2}=6x

Therefore the simplified radical form is  \sqrt{36x^2}=6x

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To find the simplified radical form of the given expression :

\sqrt{72x^3}

=\sqrt{72\times x^3}

=\sqrt{72}\times \sqrt{x^3}

=\sqrt{9\times 8}\times \sqrt{x\times x\times x}

=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}

=3\times 2\sqrt{2}\times x\sqrt{x}

\sqrt{72x^3}=6x\sqrt{2x}

Therefore the simplified radical form is  \sqrt{72x^3}=6x\sqrt{2x}

3) Given expression is \sqrt{15x^8}

To find the simplified radical form of the given expression :

\sqrt{15x^8}

=\sqrt{15\times x^8}

=\sqrt{15}\times \sqrt{x^8}

=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}

=\sqrt{15}\times x^4

\sqrt{15x^8}=\sqrt{15}x^4

Therefore the simplified radical form is  \sqrt{15x^8}=\sqrt{15}x^4

4) Given expression is \sqrt{36x^7}

To find the simplified radical form of the given expression :

\sqrt{36x^7}

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=\sqrt{36}\times \sqrt{x^7}

=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}

=6\times x^3\sqrt{x}

\sqrt{36x^7}=6x^3\sqrt{x}

Therefore the simplified radical form is  \sqrt{36x^7}=6x^3\sqrt{x}

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