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Shalnov [3]
3 years ago
7

What are the prime fractorization of 240?

Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

The prime factorization of 240, with exponents, is 24 × 3 × 5.

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iren2701 [21]
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5 0
3 years ago
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Five more than the product of four and a number is equal to the product of three and that same number increased by six.
svetlana [45]

Answer:

The number is 1.

Step-by-step explanation:

If you simplify the equation, it goes to 4x+5=3x+6. Subtract 5 from both sides and you get 4x= 3x+1. The only number that satisfies that equation is 1.

8 0
3 years ago
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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
If y = 9 inches, z = 14 inches, h = 5 inches, and w = 4 inches, what is the area of the object?
vekshin1

Answer:

126

Step-by-step explanation:

7 0
1 year ago
Please help...........
enyata [817]
On what i need to see what you are talking bout so maybe i can answer it thank u please
7 0
3 years ago
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