To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
Answer:
m= -13
Step-by-step explanation:
step1: left part times 26 is m
step2: right part times 26 is -13
so m= -13
Answer:-3x+12
Step-by-step explanation:
The answer i think is it c
Answer:
x1= -6 x2=6
Step-by-step explanation:
x^2-10 = 26
x^2 = 26 +10
x^2 = 36
x = sqrt(36)
x = -6 or x = 6 because both 6 and -6 squared are equal to 36
