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fgiga [73]
2 years ago
14

Guys please answer question #17 and 18 below please and thank you. Sorry about this photo has been rotated, I'm gonna try my bes

t to take the picture properly.

Mathematics
1 answer:
Contact [7]2 years ago
3 0

Answer:

i think its 3

Step-by-step explanation:

You might be interested in
Find the greatest common factor of 15x^2y^3 and -18x^3yz <br> The Answer has to be like _x_y_
Daniel [21]

Answer:

The greatest common factor of this would be 3x^2y

Step-by-step explanation:

In order to find this, first find the greatest common factor of the coefficients. Since 3 goes in evenly to both 15 and -18, then we know that it is a common factor.

From there we need to find the number of x's. Since the first term only has 2 x's and the second has 3, we take the lowest number. (x^2)

And since the first term has 3 y's and the second has just 1, we take the lowest number (y).

8 0
3 years ago
Solve the system of equations. 13x−y=90
SpyIntel [72]
Just squish the two equations into one equation and idk im just typing this because i apparently need a twenty character long answer

8 0
3 years ago
What is -6x+4=-50 and 5x+6=-44 also -3(7+6x)=-201 please solve these equations and show work
grandymaker [24]
Remember you can do anyting to an equation as long as ou do it to both sides



-6x+4=-50
minus 4 both sides
-6x=-54
divide both sides by -6
x=9



5x+6=-44
minus 6 both sides
5x=-50
divide both sides by 5
x=-10


-3(7+6x)=-201
normally you would distribute (that works) but it's easier to divide both sides by -3
7+6x=67
minus 7 both sides
6x=60
divide by 6 both sides
x=10
6 0
3 years ago
An amount of $ 8,000 was invested at 6% interest that is compounded yearly. The equation
sladkih [1.3K]

Answer:

The answer is 12000 roundes to the neatest thousand

Step-by-step explanation:

In your calculator just substitute 7 into t

8000 ×1.06 to the power of 7

8 0
2 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

7 0
3 years ago
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