The solutions of the graphed system of equations, y = x² + 2x – 3 and y = x – 1 are B. (–2, –3) and (1, 0)
<h3>Further explanation</h3>
Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :
<h2>D = b² - 4 a c</h2>
From the value of Discriminant , we know how many solutions the equation has by condition :
D < 0 → No Real Roots
D = 0 → One Real Root
D > 0 → Two Real Roots
Let us now tackle the problem!
Given :
<h3 />
To get a solution from the two equations above, it can be done with the following substitution method:
(x + 2) = 0 or (x - 1) = 0
x = -2 or x = 1
For x = - 2 :
∴ The solution is ( -2 , -3 )
For x = 1 :
∴ The solution is ( 1 , 0 )
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Mathematics
Chapter: Quadratic Equations
Keywords: Quadratic , Equation , Discriminant , Real , Number