Answer:
28 5 dollar bills
12 10 dollar bills
Step-by-step explanation:
You can write two equations to model this situation'
x will be the number of 5 dollar bills
y will be the number of 10 dollar bills
x+y=40
5x+10y=260
There are a couple of ways you can solve this but but I will be doing it through substitution because that looks easier (I can explain other methods if you're interested)
So we have x+y=40
If I subtract y from both sides and divide by -1 we get
-x+40=y
We can then plug this value in for y in the second equation
5x+10(-x+40)=260
Distribute the 10 and combine like terms to get
-5x+400=260
subtract 400 from both sides and divide by -5 to get
x=28
This means that there are 28 5 dollar bills. We can plug this value back in for x into our first equation to solve for y
28+y=40
Subtract 28 from both sides
y=12
This means that there were a total of 28 5 dollar bills and 12 10s
I doubled checked this in desmos and it checks out
Answer:
90 degree
Step-by-step explanation:
We start with SWV as right angle and isosceles can be found to find W
SWV = 90 so we know as isosceles they all are 90 degree met with 45 degree at line of intersections.
We see a right angle at point S on SWT and make a right angle triangle at SWT, to find T angle equal to S=90 W=45 T=45
So SWT = SRT = SRW = TRV
The middle points with R in them are all 90 at point R
The others are 90 at point S on TSW (SWT) and on all outside perimeters for the larger triangles.
2.0-c 1.0-d and then anything less (<1.0) is and f
Answer: 6 rooms
Step-by-step explanation:
3/8 rolls of wire are needed to wire a room in a house. If there are a total of 2¹/₄ rolls of wires, the number of rooms that could be wired is:
First convert to an improper fraction:
2¹/₄ = 9/4 rolls of wire
Total number of rooms that can be wired are:
= Total amount of wire available / Wires per room
= 9/4 ÷ 3/8
= 9/4 * 8/3
= 72 / 12
= 6 rooms
Answer:
-30 angle b
18 ft. h
Step-by-step explanation:
a=bh