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densk [106]
3 years ago
14

A cone is cut by a plane as shown, where the plane is not parallel to the base. The cross-section of the cone and the plane is

Mathematics
2 answers:
Leona [35]3 years ago
7 0

Answer:

Option (b) is correct.

The cross-section of the cone and the plane is an ellipse.

Step-by-step explanation:

Given : A cone is cut by a plane as shown, where the plane is not parallel to the base.

We have to determine the shape of the cross-section of the cone and the plane.

Since, The cone is cut by the plane which is not parallel to its base.

a > b

There a is the horizontal distance between the slant height of cone.

and b is vertical distance.

Thus, when a > b  

\frac{x^2}{a^2}+\frac{y^2}{b^2} =1

Thus, The cross-section of the cone and the plane is an ellipse.

steposvetlana [31]3 years ago
4 0

the plane is not horizontal and cross-section is not reach cone's base inside. so, the cross-section is an ellipse.

B)

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mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

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3 years ago
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OLEGan [10]

Answer: 30 degrees

Step-by-step explanation:

Corresponding angles of similar triangles are congruent.

5 0
2 years ago
HelppppI need help this benchmark
serious [3.7K]

Answer:

A: -6.5

Step-by-step explanation:

Take two points that we already know are on the line and find the slope

I used:

(4, -10) and (7, -30)

X1 (first x coordinate): 4

Y1 (first y coordinate): -10

X2 (second x coordinate): 7

Y2 (second y coordinate): 30

These appear to be exactly on the graph at a certain point along the line. We can't choose a coordinate pair that isn't on the line at an exact point.

Use (Y2-Y1)/(X2-X1)

(-30-(-10))/(7-4) = (-30 + 10)/3 = -20/3 = approximately -6.67.

The closest answer to that is A.

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3 years ago
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arlik [135]

Answer:

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3 years ago
Given that U is the centroid of triangle OPQ find PS.
o-na [289]

Answer:

PS=5.4

Step-by-step explanation:

The centroid divides each median in the ratio 2:1

If U is the centroid, then

3.6:x+0.8=2:1

We use ratio to obtain;

\frac{3.6}{x+0.8}=\frac{2}{1}

Cross multiply;

3.6=2(x+0.8)

Expand;

3.6=2x+1.6

Group similar terms;

3.6-1.6=2x

2=2x

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PS=PU+US

PS=3.6+1+0.8

PS=3.6+1+0.8

PS=5.4

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