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Alexandra [31]
3 years ago
5

$20 haircut; 10% tip

Mathematics
1 answer:
arlik [135]3 years ago
8 0

Answer:

I think the answer is $22.00

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1. Jason travelled from Florida to Mississauga He travelled 3/10 of the journey by lorry, 2/5 of the journey by taxi and the res
sukhopar [10]

Answer:

1. He traveled 3/ 10 by  train

2. 3/4 is the greatest

Step-by-step explanation:

3/ 10 = Iorry

2/5 = taxi

? = train

2=4

5=10

4+ 3 = 7

10 + 10=  10

13/20

12/20

15/20

17/20

5 0
4 years ago
At a popular rock-climbing site in Yosemite National Park, a randomly selected
katrin [286]

Answer:

please be more specific

Step-by-step explanation:

6 0
3 years ago
What is 9713 rounded to the place value
Akimi4 [234]
It could be 10000,9800,or 9710
6 0
3 years ago
HELP!!! Number 8!! I don’t understand what it’s asking
Maslowich

find the circumference of the circle then multiply it by 24

4 0
3 years ago
Read 2 more answers
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
4 years ago
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