You need to note first two things.
1. The function f(x) need to be a continuous function on [-3,-1] (indeed f(x) is a polynomial function, is continuous on every real number x)
2. Take the closed interval [-3,-1]
Now, evaluate f(-3) and f(-1).
So, we have f(-3) < 0 and f(-1). So, 
, then by the Intermediate Value Theorem, there exist 
such that 
.
Answer:
x=1/3
y=-7
Step-by-step explanation:
using the elimination method, you can add both equations vertically, to eliminate the x
-3x+y=-8
3x+2y=-13
3y=-21
y=-7
we then fix the value of y into the first equation
-3x+y=-8
-3x-7=-8
-3x=-8+7
-3x=-1
x=1/3
Oh.......kay.... Is that a question? It doesn't look like one.
Cubic trinomial is the correct answer
Answer:
C
Step-by-step explanation:
A modified box plot does not include the outliers in the whiskers, instead they are points outside of the whiskers
5,25,33,34,34,37,37,40,42,45,45,46,46,49,73
This data has 2 outliers 5 and 73 so we have 2 choices for a modified box plot D or D
The lowest value outside of the outliers is 25 , so C would be the logical choice
D has the lower end of the whisker too close to the outlier
